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svetlana [45]
2 years ago
12

The square root of 24025

Mathematics
1 answer:
Flura [38]2 years ago
3 0

Answer:

155

Step-by-step explanation:

✓24025=155

..,......,.................

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A boat can travel 412 miles on 103 gallons of gasoline. How much gasoline will it need to go 184 miles?
dlinn [17]

Hey there! I'm happy to help!

Let's set this up as a proportion (2 equal ratios).

\frac{miles}{gallons} =\frac{412}{103} =\frac{184}{g}

If you multiply the diagonal numbers, their products will be equal. (412×g=103×184). This is called cross multiplying. Now we can solve for g.

412g=18952

Divide both sides by 412.

g=46

Therefore, the boat will need 46 gallons of gasoline to go 184 miles.

Have a wonderful day! :D

8 0
3 years ago
How do I solve 5-2(y+1)=21
GuDViN [60]
5-2(y+1)=21

Distribute
5-2y-2= 21

Combine like terms
3-2y=21

Subtract 3 from both sides
-2y= 18

Divide both sides by -2
y= -9

Final answer: y=-9
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3 years ago
Match the steps to find the equation of the parabola with focus (-1,2) and directrix x=5
Paha777 [63]
Given that parabola has a focus of (-1,2) and directrix of x=5, Matching the steps with the equations we shall have:
1. Use (x,y)⇒choose a point from the parabola.

2. √[(x+1)²+(y-2)²]⇒Find the distance from the focus to the point on the parabola

3. √(x-5)²⇒Find the distance from the point on the parabola to the directrix

4. √[(x+1)²+(y-2)²]=√(x-5)²⇒Set the distance from focus to the point equal to the distance from directrix to the point

5. (x+2)²+(y-2)²=(x-5)² ⇒Square both sides and simplify
   y²-4y+4=-12x+24

6. x=-y²/12+y/3+5/3⇒Write the equation of the parabola
4 0
3 years ago
HELP!!!! I WILL MARK YOU BRAINLIST
Marina86 [1]

Answer:

k= 12 x= 5

Step-by-step explanation:

4 0
3 years ago
An automobile manufacturer is concerned about a possible recall of its best selling four-door sedan. If there was a recall there
goldfiish [28.3K]

Complete question is;

An automobile manufacturer is concerned about a possible recall of its best - selling four-door sedan. If there were a recall, there is a probability of 0.25 of a defect in the brake system, 0.18 of a defect in the transmission, 0.17 of a defect in the fuel system, and 0.40 of a defect in some other area.

(a) What is the probability that the defect is the brakes or the fueling system if the probability of defects in both systems simultaneously is 0.15?

(b) What is the probability that there are no defects in either the brakes or the fueling system?

Answer:

A) 0.27

B) 0.73

Step-by-step explanation:

Let B denote that there is a defect in the break system

Let T demote that there is a defect in transmission

Let F denote that there is a defect in the fuel system.

Let P denote that there is a defect in some other area.

Now, we are given;

P(B) = 0.25

P(T) = 0.18

P(F) = 0.17

P(O) = 0.40

A) We are given that probability of defects in both brakes and the fueling system simultaneously is 0.15.

Thus, it means; P(B ⋂ F) = 0.15

Now, we want to find the probability that the defect is the brakes or the fueling system. This is expressed as;

P(B ⋃ F) = P(B) + P(F) - P(B ⋂ F)

Plugging in the relevant values to give;

P(B ⋃ F) = 0.25 + 0.17 - 0.15

P(B ⋃ F) = 0.27

B) We want to find the probability that there are no defects in either the brakes or the fueling system.

This is expressed as;

P(B' ⋃ F') = 1 - P(B ⋃ F)

Plugging in relevant value;

P(B' ⋃ F') = 1 - 0.27

P(B' ⋃ F') = 0.73

7 0
3 years ago
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