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stepan [7]
2 years ago
8

.

Mathematics
1 answer:
olga_2 [115]2 years ago
6 0

Answer:

10 cups

Step-by-step explanation:

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Which polynomials are prime? Check all that apply. 15x ^ 2 + 10x - 9x + 7 20x ^ 2 - 12x + 30x - 18 6x ^ 3 + 14x ^ 2 - 12x - 28 8
NARA [144]

Answer:

15x2+10x-9x+7

8x3+20x2+3x+12

11x4+4x2-6x2-16

Step-by-step explanation:

7 0
3 years ago
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There are three numbers. The first number is twice the second number. The third number is twice the first number. The sum of the
mel-nik [20]

Answer:

x = 32 y = 16 z = 64

Step-by-step explanation:

x is the 1st number

y is the 2nd number

z is the 3rd number

The first number is twice the second number so

x = 2 y

The third number is twice the first number.

z = 2 x

Their sum is 112

x + y + z = 112

Plus in what we know:

x + y + z = 112

2 y + y + 2x = 112

3y + 2x = 112 Let's solve for y and subtract 2x from each side

3y = 112 - 2x  Divide both sides by 3

y = \frac{112 - 2x}{3}

Now plug our answer back in to solve for x.

x = 2y

x = 2 ( \frac{112 - 2x}{3} )

x = (224 - 4x) / 3    Multiply each side by 3.

3x = 224 - 4x         Add 4x to each side

3x + 4x = 224

7x = 224              Divide each side by 7

7x / 7 = 224 / 7

x = 32

Now we can solve for z.

z = 2x

z = 2 ( 32 )

z = 64

Now we can solve for the numerical value of y.

x + y + z = 112

32 + y + 64 = 112

96 + y = 112       Subtract 96 from each side.

y = 112 - 96

y = 16

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3 years ago
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Can you solve it ????
Dima020 [189]
Angle ABD=87 degrees
angle ABC+angle CBD= angle ABD
Therefore, 9x-1+6x+58=87
15x+57=87
15x=87-57
15x=30
x=30/15
x=2   


Angle ABC= 9x-1
=9(2)-1
=18-1
=17 degrees


7 0
3 years ago
Which number is larger, .8 or .1?
belka [17]
.8 because .1 is smaller
6 0
3 years ago
Can you help me with my homework
goldfiish [28.3K]

Answer:

4. Option C (3a+2) inches

5. Extraneous solution x=-5/6 because we get for width and length negative values.

Solution: Value of x is 3

Length of the box: 5 ft

Width of the box: 4 ft

Step-by-step explanation:

4. Area of a rectangle: A=12a^2-a-6 square inches

Width: w=4a-3

Length: l=?

A=w l

Replacing A by 12a^2-a-6 and w by 4a-3

12a^2-a-6 = (4a-3) l

Solving for l: Dividing both sides of the equation by 4a-3:

(12a^2-a-6) / (4a-3) = (4a-3) l / (4a-3)

Simplifying:

(12a^2-a-6) / (4a-3) = l

l = (12a^2-a-6) / (4a-3)

Factoring the numerator:

12a^2-a-6 = (4a-3)(3a+2)

Let's check it:

(4a-3)(3a+2)=4a(3a)+4a(2)-3(3a)-3(2)=12a^2+8a-9a-6→(4a-3)(3a+2)=12a^2-a-6

Replacing the numerator:

l = (4a-3)(3a+2) / (4a-3)

Simplifying:

l = (3a+2) inches


5. Length: l=(3x-5) ft

Width: w=(2x-1) ft

Height: h=2 ft

Volumen of the box: V=40 ft^3

x=?

Length: l=?

Width: w=?

V = l w h

Replacing the given:

40 ft^3 = (3x-5) ft (2x-1) ft 2 ft

40 ft^3 = 2 (3x-5)(2x-1) ft^3

40=2(3x-5)(2x-1)

Dividing both sides of the equation by 2:

40/2=2(3x-5)(2x-1)/2

Simplifying:

20=(3x-5)(2x-1)

Eliminating the parentheses on the right side of the equation applying the distributive property:

20=3x(2x)+3x(-1)-5(2x)-5(-1)

20=6x^2-3x-10x+5

Adding like terms:

20=6x^2-13x+5

Equaling to zero: Subtracting 20 from both sides of the equation:

20-20=6x^2-13x+5-20

0=6x^2-13x-15

6x^2-13x-15=0

ax^2+bx+c=0; a=6, b=-13, c=-15

Using the quadratic formula:

x=[-b+-sqrt(b^2-4ac)]/(2a)

x=[-(-13)+-sqrt((-13)^2-4(6)(-15))]/(2(6))

x=[13+-sqrt(169+360)]/12

x=[13+-sqrt(529)]/12

x=[13+-23]/12

x1=(13-23)/12=(-10)/12=-10/12=-(10/2)/(12/2)→x1=-5/6

x2=(13+23)/12=36/12→x2=3


With x=-5/6

l=(3x-5) ft

l=(3(-5/6)-5) ft

l=(-5/2-5) ft

l=-(5/2+5) ft

l=-(5+2(5))/2 ft

l=-(5+10)/2 ft

l=-15/2 ft < 0. The length cannot be a negative number then x=-5/6 is a extraneous solution.

w=(2x-1) ft

w=(2(-5/6)-1) ft

w=(-5/3-1) ft

w=-(5/3+1) ft

w=-(5+3(1))/3 ft

w=-(5+3)/3 ft

w=-8/3 ft <0. The width cannot be a negative number then x=-5/6 is a extraneous solution.


With x=3

l=(3x-5) ft

l=(3(3)-5) ft

l=(9-5) ft

l=4 ft

w=(2x-1) ft

w=(2(3)-1) ft

w=(6-1) ft

w=5 ft

and h=2 ft

Let's check the volume

V= w l h

V=(5 ft)(4 ft)(2 ft)

V=40 ft^3 Correct

7 0
3 years ago
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