Explanation:
The given data is as follows.
q = 6.0 nC =
inner radius (r) = 1.0 cm = 0.01 m (as 1 cm = 100 m)
So, there will be same charge on the inner surface as the charge enclosed with an opposite sign.
Formula to calculate the charge density is as follows.
.......... (1)
Since, area of the sphere is as follows.
A = ........... (2)
Hence, substituting equation (2) in equation (1) as follows.
=
=
or, = 4.77
Thus, we can conclude that the resulting charge density on the inner surface of the conducting sphere is 4.77 .
Answer:
Explanation:
m = 0.5 kg
A = 0.15 m
vmax = 1.25 m/s
vmax = ω x A
1.25 = ω x 0.15
ω = 8.33 rad/s
(a) Let the spring constant be k
k = ω² m = 8.33 x 8.33 x 0.5 = 34.7 N/m
(b) Maximum acceleration, a max = ω² A = 8.33 x 8.33 x 0.15 = 10.42 m/s^2
(c) Let f be the frequency
ω = 2 π f
8.33 = 2 x 3.14 x f
f = 1.326 Hz
(d) Total energy
E = 1 /2 m x ω² x A² = 0.5 x 0.5 x 8.33 x 8.33 x 0.15 x 0.15 = 0.39 J
Answer:
a
The mass is
b
The velocity is
Explanation:
From the question we are told that
The speed of the protons is
The mass of the protons is
The speed of the rebounding protons are
The negative sign shows that it is moving in the opposite direction
Now according to the law of energy conservation mass of one nucleus of the unknown element. is mathematically represented as
Where is the mass of a single proton
So substituting values
The mass of on proton is
So
Now according to the law of linear momentum conservation the speed of the unknown nucleus immediately after such a collision is mathematically evaluated as
Now because before collision the the nucleus was at rest
So
=>
Recall that
So
=>
substituting values
Current always returns to the negative terminal.
<u>Explanation</u>:
Current flows from a positive to a negative terminal. It is due to the flow of negative electrons to positive side. The current flows from a high potential to a low potential. There is high concentration of electrons at the positive terminal and low concentration at the negative terminal. When the circuit is complete the electrons move from a high concentration to low concentration i.e; from positive terminal to negative terminal.
Can you get a better pic so i can read it