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3 years ago

Im giving out brainliest ;)

Mathematics

2 answers:

Zanzabum3 years ago

8 0

Answer:

the vertical intercept is 600. in the concept it means that the grandparents put $600 into the account when it first opened

vladimir1956 [14]3 years ago

4 0

Answer:

Step-by-step explanation:

the vertical intercept is 600. in the concept it means that the grandparents put $600 into the account when it first opened.

You might be interested in

What is the volume of a cone when the radius is 6 and the height is 13

lidiya [134]

Answer:

<h2>489.84 units³</h2>

Step-by-step explanation:

Given,

Radius ( r ) = 6

Height ( h ) = 13

Volume of cone = ?

Now, Let's find the volume of cone:

$= \pi \: {r}^{2} \frac{h}{3}$

plug the values

$= 3.14 \times {6}^{2} \times \frac{13}{3}$

Evaluate the power

$= 3.14 \times 36 \times \frac{13}{3}$

Calculate

$489.84$ units³

Hope this helps..

Best regards!!

6 0

3 years ago

A ship leaves port at 10 miles per hour, with a heading of N 35° W. There is a warning buoy located 5 miles directly north of th

Leno4ka [110]

The value of the angle subtended by the distance of the buoy from the

port is given by sine and cosine rule.

The bearing of the buoy from the is approximately 307.35°

Reasons:

Location from which the ship sails = Port

The speed of the ship = 10 mph

Direction of the ship = N35°W

Location of the warning buoy = 5 miles north of the port

Required: The bearing of the warning buoy from the ship after 7.5 hours.

Solution:

The distance travelled by the ship = 7.5 hours × 10 mph = 75 miles

By cosine rule, we have;

a² = b² + c² - 2·b·c·cos(A)

Where;

a = The distance between the ship and the buoy

b = The distance between the ship and the port = 75 miles

c = The distance between the buoy and the port = 5 miles

Angle ∠A = The angle between the ship and the buoy = The bearing of the ship = 35°

Which gives;

a = √(75² + 5² - 2 × 75 × 5 × cos(35°))

By sine rule, we have;

$\displaystyle \frac{a}{sin(A)} = \mathbf{ \frac{b}{sin(B)}}$

Therefore;

$\displaystyle sin(B)= \frac{b \cdot sin(A)}{a}$

Which gives;

$\displaystyle sin(B) = \mathbf{\frac{75 \cdot sin(35^{\circ})}{\sqrt{75^2 + 5^2 - 2 \times 75\times5\times cos(35^{\circ}) } }}$

$\displaystyle B = arcsin\left( \frac{75 \cdot sin(35^{\circ})}{\sqrt{75^2 + 5^2 - 2 \times 75\times5\times cos(35^{\circ}) } }\right) \approx 37.32^{\circ}$

Similarly, we can get;

$\displaystyle B = arcsin\left( \frac{75 \cdot sin(35^{\circ})}{\sqrt{75^2 + 5^2 - 2 \times 75\times5\times cos(35^{\circ}) } }\right) \approx \mathbf{ 142.68^{\circ}}$

The angle subtended by the distance of the buoy from the port, C is therefore;

C ≈ 180° - 142.68° - 35° ≈ 2.32°

By alternate interior angles, we have;

The bearing of the warning buoy as seen from the ship is therefore;

Bearing of buoy ≈ 270° + 35° + 2.32° ≈ 307.35°

Learn more about bearing in mathematics here:

brainly.com/question/23427938

5 0

2 years ago

Brainliest Please do one of the above (I would appreciate if you did more then one)

Temka [501]

Answer:

a) 52.5 ft. b)40.1ft c)12.5ft d) 72.6

Step-by-step explanation:

a) The height of the lighthouse is 84ft, and the angle of elevation is 58 degrees.

tan58=84/x

find x by dividing 84 by tan58, and you get 52.5ft.

b) do the same thing, except 131 is in the base of the right triangle shape. That being said, do tan17=x/131.

multiply 131 by tan17, and you get x=40.1 feet.

c) This question wants you to find the length of the slide, (basically the hypotenuse).

given the angle to be 46, do sin46=9/x

since sin is opp/hyp

9/sin46= 12.5ft

d) Find the angle of elevation by using inverse tan given the base to be 5, and the height to be 16ft.

tan^-1=(16/5)=theta

x=72.6 hope this helps!

5 0

2 years ago

Read 2 more answers

HELP PLSS !!! Will mark as brainiest

Natasha_Volkova [10]

Answer:

$1709.92cm^3$

Step-by-step explanation:

$V=\pi r^2h=\pi *3^2*7=197.92cm^2$ (cylinder)

$V=whl=14*9*12=1512cm^3$ (rectangular prism)

$197.92+1512=1709.92cm^3$ (whole shape)

5 0

3 years ago

If the numbers 4, 5 and 6 are each used exactly once to replace the letters in the expression A ( B − C ), what is the least pos

guapka [62]

Answer:

The least possible result is -10.

Step-by-step explanation:

Given the numbers 4, 5 and 6 are to be chosen one of the letters A, B or C.

First of all,

Let A = 4, B = 5 and C = 6

$A(B-C) = 4 \times (5-6) = 4 \times -1 = -4$

Let A = 4, B = 6 and C = 5

$A(B-C) = 4 \times (6-5) = 4 \times 1 = 4$

Let A = 5, B =4 and C = 6

$A(B-C) = 5 \times (4-6) = 5 \times -2 = -10$

Let A = 5, B = 6 and C = 4

$A(B-C) = 4 \times (6-4) = 4 \times 2 = 8$

Let A = 6, B = 4 and C = 5

$A(B-C) = 6 \times (4-5) = 6 \times -1 = -6$

Let A = 6, B = 5 and C = 4

$A(B-C) = 6 \times (6-5) = 6 \times 1 = 6$

Summarizing the above values in the form of a table:

$\begin{center}\begin{tabular}{ c c c c}A & B & C & A(B-C)\\ 4 & 5 & 6 & -4\\ 4 & 6 & 5 & 4\\ 5 & 4 & 6 & -10\\ 5 & 6 & 4 & 10\\ 6 & 4 & 5 & -6\\ 6 & 5 & 4 & 6\end{tabular}\end{center}$

So, the least possible result is -10.

3 0

3 years ago