All categories

3 years ago

13. For the arithmetic sequence: 6, 12, 18, 24,...

Mathematics

1 answer:

serg [7]3 years ago

4 0

a_15 = 90

a_n = 6n

Step-by-step explanation:

Given sequence is:

6, 12, 18, 24,...

First of all we have to find the common difference. The common difference is the difference between consecutive terms of an arithmetic sequence.

Here,

$d=a_2-a_1 = 12-6 = 6\\d=a_3-a_2= 18-12 = 6$

The general form for arithmetic sequence is:

$a_n=a_1+(n-1)d$

Putting the values for a_1 and d

$a_n=6+(n-1)(6)\\a_n=6+6n-6\\a_n=6n$

$a_{15} = 6(15)\\=90$

<u>b) Write an equation for the nth term.</u>

The equation is: a_n=6n

Keywords: Arithmetic sequence, Common Difference

Learn more about arithmetic sequence at:

#LearnwithBrainly

You might be interested in

What is 5 + 5 + 5 + 5 + 6 + 7 + 5 + 6 + 4 + 4+ 4 + 6+ 3 + 3 + 1 + 9?

elena-14-01-66 [18.8K]

Answer:

5,555,675,644,463,319

Step-by-step explanation:

plz mark brainly

JK 78 LOL

7 0

3 years ago

Read 2 more answers

Part F

mihalych1998 [28]

Answer:

The geometric mean of the measures of the line segments AD and DC is 60/13

Step-by-step explanation:

Geometric mean: BD² = AD×DC

BD = √(AD×DC)

hypotenuse/leg = leg/part

ΔADB: AC/12 = 12/AD

AC×AD = 12×12 = 144

AD = 144/AC

ΔBDC: AC/5 = 5/DC

AC×DC = 5×5 = 25

DC = 25/AC

BD = √[(144/AC)(25/AC)]

BD = (12×5)/AC

BD= 60/AC

Apply Pythagoras theorem in ΔABC

AC² = 12² + 5²

AC² = 144+ 25 = 169

AC = √169 = 13

BD = 60/13

The geometric mean of the measures of the line segments AD and DC is BD = 60/13

6 0

3 years ago

A new test has been developed to detect a particular type of cancer. The test must be evaluated before it is put into use. A med

Troyanec [42]

The tree diagram of the problem above is attached
There are four outcomes of the two events,

First test - Cancer, Second Test - Cancer, the probability is 0.0396
First test - Cancer, Second Test - No Cancer, the probability is 0.0004
First test - No Cancer, Second Test - There is cancer, the probability is 0.0096
First test - No cancer, Second Test - No cancer, the probability is 0.9054

The probability of someone picked at random has cancer given that test result indicates cancer is $\frac{0.0396}{0.0396+0.0096}= \frac{33}{41}$

The probability of someone picked at random has cancer given that test result indicates no cancer is $\frac{0.0396}{0.0004+0.9504} = \frac{99}{2377}$