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Reptile [31]
3 years ago
9

13. For the arithmetic sequence: 6, 12, 18, 24,...

Mathematics
1 answer:
serg [7]3 years ago
4 0

a_15 = 90

a_n = 6n

Step-by-step explanation:

Given sequence is:

6, 12, 18, 24,...

First of all we have to find the common difference. The common difference is the difference between consecutive terms of an arithmetic sequence.

Here,

d=a_2-a_1 = 12-6 = 6\\d=a_3-a_2= 18-12 = 6

The general form for arithmetic sequence is:

a_n=a_1+(n-1)d

Putting the values for a_1 and d

a_n=6+(n-1)(6)\\a_n=6+6n-6\\a_n=6n

<u>a) Find a15</u>

a_{15} = 6(15)\\=90

<u>b) Write an equation for the nth term.</u>

The equation is: a_n=6n

Keywords: Arithmetic sequence, Common Difference

Learn more about arithmetic sequence at:

  • brainly.com/question/10703930
  • brainly.com/question/10772025

#LearnwithBrainly

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Answer:

For every 1 gallon of Orange Juice the factory makes 6 gallons of Apple Juice so id say the ratio is 1:6

Step-by-step explanation:

8 0
3 years ago
A line has a slope of -5 and passes through the point (2, 2). What is the equation for this line?
koban [17]
To determine the equation of the line, we use the point slope form equation for this problem. It is expressed as:

y - y1 = m(x - x1)

We substitute the given values in the problem to the equation.

y - 2 = -5(x - 2)
y = -5x +10+2
y = -5x +12 
4 0
3 years ago
A bicycle lock has a four-digit code. The possible digits, 0 through 9, cannot be repeated. What is the probability that the loc
kozerog [31]
First let's find the number of the elements in the sample space, that is the total number of codes that can be produced.

The first digit is any of {0, 1, 2...,9}, that is 10 possibilities
the second digit is any of the remaining 9, after having picked one. 
and so on...

so in total there are 10*9*8*7 = 5040 codes.

a. What is the probability that the lock code will begin with 5?

Lets fix the first number as 5. Then there are 9 possibilities for the second digit, 8 for the third on and 7 for the last digit.

Thus, there are 1*9*8*7=504 codes which start with 5.

so 

P(first digit is five)=\frac{n(first -digit- is- 5)}{n(all-codes)}= \frac{1*9*8*7 }{10*9*8*7 }= \frac{1}{10}=0.1

b. <span>What is the probability that the lock code will not contain the number 0? 

from the set {0, 1, 2...., } we exclude 0, and we are left with {1, 2, ...9}

from which we can form in total 9*8*7*6 codes which do not contain 0.

P(codes without 0)=n(codes without 0)/n(all codes)=(9*8*7*6)/(10*9*8*7)=6/10=0.6

Answer:

0.1 ; 0.6</span>
4 0
3 years ago
Read 2 more answers
I really need help with this, ASAP! Thank you!
mylen [45]
Example 1:
____÷418 = 218
To find the answer to a question like this it's simple. All you do is multiple the two numbers, 418x218, and your answer is: 91,124
Check your work!
91,124÷418= 218 correct!
7 0
3 years ago
I need 1-5 and 8 and 9 solved
meriva

Answer:

1. A

2. H

3.B

4. H

5. A

Those are the answers

Step-by-step explanation:

1. 30 - 2(-8)= 46

2. BODMAS applied 6-7 =-1

3. 45/-5=-9

4. Sum is h +73

5.BODMAS applied 60 /6 = 10

8 0
3 years ago
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