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3 years ago

K=5/9(F+459.67) solve for F in terms of K

Mathematics

1 answer:

Mila [183]3 years ago

5 0

Answer:

F = 5.67503704

Step-by-step explanation:

K=5/9(F+459.67) K = 5/9F / 5/9 = 255.376667 / 5/9 = F = 5.67503704

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Three more Than the quotient of a number and 2 is equal to 7

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Answer:

Step-by-step explanation:

the quotient is the result of division

let x represent the number

(x/2) + 3 = 7

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3 years ago

A line passes through (-3,-5) and (5,-4) write equation in point slope form

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Answer:

work is shown and attached

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3 years ago

The measure of two complementary angles are in the ratio 1 : 4. What are the degree measures of the two angles?

AlladinOne [14]

Since the angles are complementary, they add to 90°. So we can write the equation:
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3 years ago

The lengths of the bases of the right trapezoid are 9 cm and 18 cm. The length of a longer leg is 15 cm. Find the area of the tr

finlep [7]

Firstly, we will draw figure

now, we will draw a altitude from B to DC that divides trapezium into rectangle and right triangle

because of opposite sides of rectangle ABMD are congruent

so,

DM=AB=9

CM=CD-DM

CM=18-9

CM=9

now, we can find BM by using Pythagoras theorem

$BM=\sqrt{BC^2-CM^2}$

now, we can plug values

we get

$BM=\sqrt{15^2-9^2}$

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now, we can find area of trapezium

$A=\frac{1}{2} (AB+CD)*(BM)$

now, we can plug values

and we get

$A=\frac{1}{2} (9+18)*(12)$

$A=162cm^2$

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3 years ago

A data set includes 108 body temperatures of healthy adult humans having a mean of 98.3degrees°F and a standard deviation of 0.6

mylen [45]

<h2>Answer with explanation:</h2>

The confidence interval for population mean is given by :-

$\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}$

Given : Sample size : n=106

Sample mean : $\overline{x}=98.3^{\circ}\ F$

Standard deviation : $\sigma= 0.69^{\circ}F$

Significance level : $\alpha: 1-0.99=0.01$

Critical value : $z_{\alpha/2}=2.576$

Then , 99% confidence interval estimate of the mean body temperature of all healthy humans will be :-

$98.3\pm (2.576)\dfrac{0.69}{\sqrt{106}}\\\\\approx98.3\pm0.173=(98.3-0.173,\ 98.3+0.173)=(98.127,\ 98.473)$

Since 98.6 is higher than the upper limit of the confidence interval (98.473), then this suggest that the mean body temperature could be lower then 98.6 degrees.

The best estimate of population mean is always the sample mean. $\mu=\overline{x}=98.3^{\circ}\ F$

7 0

3 years ago