Answer:
zero goats and 120 Ilamas to get profit of $15,120
Step-by-step explanation:
Goats: G
Ilamas: l
Explicit constraints:
2G + 5l ≤ 400
100G+ 80l≤ 13,200
Implicit constraints
G≥0
I≥0
P= 84G+ 126l
See attachment for optimal area
substituting coordinats of optimal region in profit equation to get profit
When G= 132, l=0
P=84(132) + 126(0)
P=11,088
When G=0, l=120
P=84(0)+ 126(120)
P = 15120
When G= 100, l=40
P=84(100)+126(40)
P=13440
Answer:
A
Step-by-step explanation:
Answer: The group wants to raise $1,200.
Step-by-step explanation:
We can use a proportion to solve.
part/whole = percent/100
If we insert the values:
276/x = 23/100
We can cross multiply.
276 x 100 = 27,600
27,600 / 23 = 1,200
$1,200 is the answer.
Answer:
1st = 4×10 ^-9
2nd= 4×10^1
3rd = 4×10^7
4th = 4×10^-5
Step-by-step explanation:
for whole numbers you just have to count from the ending till the number indicated beside the x10
for decimals you count from the front starting at the decimal till you cover the whole number
Answer:
16 lawns
Step-by-step explanation:
set up a proportion:
(4/5 ÷ 1) = (x÷20)
cross-multiply:
5x = 80
x = 16
