The coefficients could be chosen to be the coefficients in the Maclaurin series of
.
We have
It follows that ,
,
, and
.
What is the slope of the line through points (−2, 3) and (6, 1)?
2 answers:
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Answer:
(1,0)
Step-by-step explanation:
y>-3x +3
y≥ 2x-2
If we plot these two inequalities, we can see where the lines intersect, See attached graph.
They intersect at (1,0)
We can also do this mathematically:
y>-3x +3
<u>- (y≥ 2x-2)</u>
0 -5x + 5
5x 5
x 1
If x = 1:
y≥ 2x-2
y≥ 2(1)-2
y≥ 0
(x,y) = (1,0)
For this case we must find the quotient of the following expression:
We have to:
By definition of power properties we have:
So so:
Answer:
Option A