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anzhelika [568]
2 years ago
10

3 Tom just had an appointment with an insurance agent, whom he asked what he meant by the word premium. What does it mean? ​

Mathematics
1 answer:
Marysya12 [62]2 years ago
4 0

A premium is a payment Tom would make to the insurance company. This payment is usually once a month.

Keep in mind that this is <u>not</u> money that is paid out to Tom. The amount he would pay per month would depend on a number of risk factors. The higher the risk, the larger the premium. For instance, if Tom is buying health insurance and he lives a fairly unhealthy lifestyle (eg: smoker who doesn't exercise), then his premiums are likely to be higher compared to those who stay fit. This is because Tom will likely use health services more often compared to fit individuals, and thereby meaning that the insurance company is paying out more.

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Llana [10]
The answer to your question is $720
6 0
2 years ago
One number is three more than the other. their sum is thirty three. find the numbers
adell [148]
The numbers are 15,18
They add to 33 and a difference of 3
3 0
2 years ago
A circle has the order pairs (-1, 2) (0, 1) (-2, -1) what is the equation . Show your work.
olga55 [171]
We know that:

(x-a)^2+(y-b)^2=r^2

is an equation of a circle.

When we substitute x and y (from the pairs we have), we'll get a system of equations:

\begin{cases}(-1-a)^2+(2-b)^2=r^2\\(0-a)^2+(1-b)^2=r^2\\(-2-a)^2+(-1-b)^2=r^2\end{cases}

and all we have to do is solve it for a, b and r.

There will be:

\begin{cases}(-1-a)^2+(2-b)^2=r^2\\(0-a)^2+(1-b)^2=r^2\\(-2-a)^2+(-1-b)^2=r^2\end{cases}\\\\\\&#10;\begin{cases}1+2a+a^2+4-4b+b^2=r^2\\a^2+1-2b+b^2=r^2\\4+4a+a^2+1+2b+b^2=r^2\end{cases}\\\\\\&#10;\begin{cases}a^2+b^2+2a-4b+5=r^2\\a^2+b^2-2b+1=r^2\\a^2+b^2+4a+2b+5=r^2\end{cases}\\\\\\&#10;

From equations (II) and (III) we have:

\begin{cases}a^2+b^2-2b+1=r^2\\a^2+b^2+4a+2b+5=r^2\end{cases}\\--------------(-)\\\\a^2+b^2-2b+1-a^2-b^2-4a-2b-5=r^2-r^2\\\\-4a-4b-4=0\qquad|:(-4)\\\\\boxed{-a-b-1=0}

and from (I) and (II):

\begin{cases}a^2+b^2+2a-4b+5=r^2\\a^2+b^2-2b+1=r^2\end{cases}\\--------------(-)\\\\a^2+b^2+2a-4b+5-a^2-b^2+2b-1=r^2-r^2\\\\2a-2b+4=0\qquad|:2\\\\\boxed{a-b+2=0}

Now we can easly calculate a and b:

\begin{cases}-a-b-1=0\\a-b+2=0\end{cases}\\--------(+)\\\\-a-b-1+a-b+2=0+0\\\\-2b+1=0\\\\-2b=-1\qquad|:(-2)\\\\\boxed{b=\frac{1}{2}}\\\\\\\\a-b+2=0\\\\\\a-\dfrac{1}{2}+2=0\\\\\\a+\dfrac{3}{2}=0\\\\\\\boxed{a=-\frac{3}{2}}

Finally we calculate r^2:

a^2+b^2-2b+1=r^2\\\\\\\left(-\dfrac{3}{2}\right)^2+\left(\dfrac{1}{2}\right)^2-2\cdot\dfrac{1}{2}+1=r^2\\\\\\\dfrac{9}{4}+\dfrac{1}{4}-1+1=r^2\\\\\\\dfrac{10}{4}=r^2\\\\\\\boxed{r^2=\frac{5}{2}}

And the equation of the circle is:

(x-a)^2+(y-b)^2=r^2\\\\\\\left(x-\left(-\dfrac{3}{2}\right)\right)^2+\left(y-\dfrac{1}{2}\right)^2=\dfrac{5}{2}\\\\\\\boxed{\left(x+\dfrac{3}{2}\right)^2+\left(y-\dfrac{1}{2}\right)^2=\dfrac{5}{2}}
7 0
3 years ago
What is 8 thousands 15 hundreds 15 Tens 18 ones written in standard form ?
ryzh [129]
I'm not sure what you are trying to convey, but you cannot have more than one digit, so this is imposible
8 0
3 years ago
Read 2 more answers
I need the answers to this ASAP
Doss [256]

Answer:

First Answer: A = $ 4,247.03

A = P + I where

P (principal) = $ 4,000.00

I (interest) = $ 247.03

Second Answer : A = $ 6,325.22

A = P + I where

P (principal) = $ 5,500.00

I (interest) = $ 825.22

Third Answer: A = $ 7,735.55

A = P + I where

P (principal) = $ 7,000.00

I (interest) = $ 735.5

Fourth Answer: A = $ 7,735.55

A = P + I where

P (principal) = $ 7,000.00

I (interest) = $ 735.55

Step-by-step explanation:

HOPE IT HELPS MARK ME BRAINLIEST :)

7 0
3 years ago
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