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Kipish [7]
3 years ago
9

Write an expression in simplest form for the perimeter of the exercise mat

Mathematics
1 answer:
Verizon [17]3 years ago
6 0
The simplest expression is (2w)+(2*3w), because to calculate perimeter, you have to use this formula: 2length+2width.
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How to solve for 1000(x-2)=75000
Andrews [41]
So, first you divide 75000 by 1000. Then you add 2 to each side. Then that's the answer, x=77
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3 years ago
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Cara is 14 years old . This is twice as old as her brother . How old is her brother
Alenkinab [10]

Cara's brother is 7 years old.

14 is twice as much as 7 (7 * 2 = 14).

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3 years ago
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Solve for substitution 8x+2y=13 and 4x+y=11
damaskus [11]
Solving for X:
1) y=-8x+6.5   y=-4x+11
2) -8x+6.5=-4x+11
3) -8x=-4x+11-6.5        (Subtract 6.5 from both sides)
4) -8x+4x=11-6.5         (Add 4x to both sides)
5)-4x=4.5
5)x=-1.125

Solving for Y:
y=-8(-1.125)+6.5
y=9+6.5
y=15.5

y=-4(-1.125)+11
y=4.5+11
y=15.5

x=-1.125
y=15.5
or
(-1.125,15.5)
7 0
3 years ago
WHAT IS THE LENGTH!!!
Murljashka [212]

The figure is a trapezoid (or trapezium), and the exact length of the trapezoid is 5 units

<h3>How to determine the length?</h3>

The figure is a trapezoid with the following parameters:

Area = 107.95

Base= 12

Height = 12.7

Length = x

The area of a trapezoid is:

Area = 0.5 * (Base + Length) * Height

So, we have:

0.5 * (12 + Length) * 12.7 = 107.95

Evaluate the product

(12 + Length) * 6.35 = 107.95

Divide both sides by 6.35

12 + Length = 17

Subtract 12 from both sides

Length =  5

Hence, the length of the trapezoid is 5 units

Read more about areas at:

brainly.com/question/24487155

#SPJ1

6 0
1 year ago
Describe the graph that would be used to solve the equation –x2 + 4 = x + 2 using a system of equations. How will you use the gr
gayaneshka [121]

Answer:

The solutions are (-2 , 0) and (1 , 3)

Step-by-step explanation:

∵ -x² + 4 = x + 2

* y = -x² + 4 ⇒ is quadratic represented by parabola

 The parabola open downward because coefficient of x² is negative

 The x-coordinate of its vertex = -b/2a, where b is the

  coefficient of x and a is the coefficient of x²

∴ x = 0/2(-1) = 0

∴ The y-coordinate of the vertex = (0)² + 4 = 4

∴ The maximum point of the parabola is (0 , 4)

∵ -x² + 4 intersects x-axis at y = 0

∴ -x² + 4 = 0 ⇒ -x² = -4 ⇒ x² = 4

∵ x² = 4

∴ x = ±√4 = ± 2

∴ the parabola intersects x-axis at -2 , 2

∵ y = x + 2 represented by a line its slope = 1

  It intersects y-axis at 2

∵ x + 2 intersects x-axis at y = 0

∴ x + 2 = 0

∴ x = -2

∴ The parabola and the line intersect each other at

  x = -2 and y = 0

To find all the point of intersection between the 2 equations we will solve them as a system of equations

∵ y= -x² + 4  and y = x + 2

∴ -x² + 4 = x + 2

∴ -x² + 4 - x - 2 = 0

∴ -x² - x + 2 = 0 ⇒ × -1

∴ x² + x - 2 = 0 ⇒ factorize

∴ (x + 2)(x - 1) = 0

∴ x + 2 = 0 ⇒ x = -2

∴ x - 1 = 0 ⇒ x = 1

* when x = -2 ⇒ y = -2 + 2 = 0 ⇒ (-2 , 0)

* when x = 1 ⇒ y = 1 + 2 = 3 ⇒ (1 , 3)

The solution graphically

3 0
2 years ago
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