WHich system of inequalities is shown?
1 answer:
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Answer: a = 4, b = 163,422
<u>Step-by-step explanation:</u>
P is the new population, P₀ is the initial population, k is the growth rate, t is the time elapsed.
Part a) What do we know?
P = 7003
P₀ = unknown
k = .21 <em>(converted 21% into a decimal)</em>
t = 36 yrs <em>(2006 - 1970) </em>
<em>need to solve for P₀</em>
7003 = P₀ (1920)
3.6 = P₀
rounded to the nearest whole number = 4
Part b) What do we know?
P = unknown
P₀ = 7003
k = .21 <em>(converted 21% into a decimal)</em>
t = 15 yrs <em>(2021 - 2006) </em>
<em>need to solve for P₀</em>
P = 7003(23.33)
P = 163,422.46
rounded to the nearest whole number = 163,422
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Answer: 2, -1
<u>Step-by-step explanation:</u>
eˣ² = eˣ * e²
eˣ² = eˣ⁺²
x² = x + 2
x² - x - 2 = 0
(x - 2)(x + 1) = 0
x - 2 = 0 or x + 1 = 0
x = 2 or x = -1
Check both answer for validity:
eˣ² = eˣ⁺²
e⁴ = e⁴ or e¹ = e¹
TRUE TRUE
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Answer: 0 = ln 1
<u>Step-by-step explanation:</u>
-10 = ln 1 - 10 <em>log rules say division is subtraction</em>
0 = ln 1
Answer:
The constant force exerted on the ball by the wall is 119.68 N.
Step-by-step explanation:
Consider the provided information.
It is given that the mass of the ball is m = 2.2 kg
The initial velocity of the ball towards left is 7.4 m/s
So the momentum of the ball when it strikes is =
The final velocity of the ball is -6.2 m/s
So the momentum of the ball when it strikes back is =
Thus change in moment is:
The duration of force exerted on the ball t = 0.25 s
Therefore, the constant force exerted on the ball by the wall is:
Hence, the constant force exerted on the ball by the wall is 119.68 N.