Area of a rectangle of length L and width W is A = LW.
Here, A = 60 ft^2 = (12 ft)(2x-3 ft). Let's find the values of x for which the area =60 ft^2, and then the values of x for which the area is greater than 60 ft^2.
60 = 12(2x-3) becomes 5 = 2x - 3 after dividing both sides by 12.
Adding 3 to both sides of this last equation results in 8 = 2x, so x = 4.
Does (12 ft)(2[4 ft] - 3) = 60? Does (12 ft)(5 ft) = 60 sq ft? YES.
The area of this rectangle will be greater than 60 sq ft if x>4 ft. (answer)
the answer is d or the last one
Answer:
C
Step-by-step explanation:
3/5 + 1/4 = 0.85
0.85 as a fraction is 17/20
So the answer is C
Answer:
42 cm
Step-by-step explanation:
Area of rectangle (shaded area):
length × breadth
length: 7 cm
breadth: 7 - 2(0.5) = 6 cm
7 × 6 = 42 cm
Answer:
25x^2 - 16y^2 - 400 = 0
Step-by-step explanation:
