All categories

3 years ago

Suppose that each quater at a

Mathematics

1 answer:

dsp733 years ago

3 0

Tuition- 3,645
Fees- 110

You might be interested in

Prove that an = 4^n + 2(-1)^nis the solution to

olga nikolaevna [1]

Answer:

See proof below

Step-by-step explanation:

We have to verify that if we substitute $a_n=4^n+2(-1)^n$ in the equation $a_n=3a_{n-1}+4a_{n-2}$ the equality is true.

Let's substitute first in the right hand side:

$3a_{n-1}+4a_{n-2}=3(4^{n-1}+2(-1)^{n-1})+4(4^{n-2}+2(-1)^{n-2})$

Now we use the distributive laws. Also, note that $(-1)^{n-1}=\frac{1}{-1}(-1)^n=(-1)(-1)^{n}$ (this also works when the power is n-2).

$=3(4^{n-1})+6(-1)^{n-1}+4(4^{n-2})+8(-1)^{n-2}$

$=3(4^{n-1})+(-1)(6)(-1)^{n}+4^{n-1}+(-1)^2(8)(-1)^{n}$

$=4(4^{n-1})-6(-1)^{n}+8(-1)^{n}=4^n+2(-1)^n=a_n$

then the sequence solves the recurrence relation.

4 0

3 years ago

What equation does the model represent?

Vesnalui [34]

It would be 62+23=94 because you'll need to add the tens and the ones, then add it up

I think-_-

7 0

3 years ago

32 people volunteers to donate blood. n dident have he health requirment so they couldent donate the rest of the volunteers dona

Vesna [10]

Answer:

the equation representing total amount of blood donated is $470(32-n)=15040-470n \ ml$ .

Step-by-step explanation:

Total number of volunteers = 32

number of volunteers couldn't donate blood = $n$ .

So Number of volunteers who donated blood can be calculated by subtracting number of volunteers couldn't donate blood from Total number of volunteers.

Framing in equation form we get;

So, the number of remaining volunteers who donated blood = $32-n$ .

Each of these volunteers donated blood = 470 ml

Now Total Amount of Blood donated is equal to Amount each of these volunteers donated blood times the number of volunteers who donated blood.

Framing in the equation form we get;

total amount of blood donated milliliters = $470(32-n)=15040-470n \ ml$

Hence the equation representing total amount of blood donated is $470(32-n)=15040-470n \ ml$ .

4 0

3 years ago

If line P bisects segmentAD at point O and if AO=z+4 and AD =3z-11, find OD

sleet_krkn [62]

Answer:

Line P bisects AD at O.

AD = AO + OD

(3z - 11) = (z + 4) + OD

(3z - 11) - (z + 4) = OD

3z - 11 - z - 4 = OD

2z -15 = OD

3 0

3 years ago

If a = -2, b = -6, c = -4, and d = -3, evaluate the following expressions.

abruzzese [7]

It’s Has to be B because if you had the negative numbers you get -12

6 0

3 years ago