Hello I had some math work if anyone who like to help , I can send you $ thank you

Mathematics

2 answers:

vlada-n [284]3 years ago

5 0

I can try to help. . . . . . . .

4vir4ik [10]3 years ago

3 0

Answer: i don't need the money but i can try to help you

Step-by-step explanation:

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A company needs to package 2,400 pencils. A box in the shape of a rectangular prism can hold 60 pencils. A cylindrical container

Sergio039 [100]

Answer:

The rectangular prism boxes should be used because they will cost the company $2.50 less than using the cylindrical containers.

Step-by-step explanation:

Box

2400/60 * .5 = 20

Cylinder

2400/80 * .75 = 22.5

Box cost 2.50 less

7 0

3 years ago

Read 2 more answers

Convert the polar equation r = 2 secØ to a Cartesian equation.y = 2x = 2x^2 = 2

ss7ja [257]

Polar and cartesian equation<h2>Initial explanation</h2>

Let's analyze the relation between r and x and y:

We have that between the indicated value of r (of the polar coordinates) and x and y (of the cartesian coordinates) there is a relation because they form a triangle. If r changes, then the value of x and y will change.

<h2>STEP 1: given equation</h2>

Using the given equation

r = 2 secØ

we have that

$\begin{gathered} r=2secØ \\ \downarrow \\ \frac{r}{2}=secØ \end{gathered}$ <h2>STEP 2: secØ equation</h2>

Observing the image of the initial explanation we have a right triangle, we know that the equation of

secØ for any right triangle is given by:

$\sec Ø=\frac{\text{hypotenuse}}{\text{adjacent side}}$

In this case,

hypotenuse = r

adjacent side = x

then,

$\begin{gathered} \sec Ø=\frac{\text{hypotenuse}}{\text{adjacent side}}=\frac{r}{x} \\ \sec Ø=\frac{r}{x} \end{gathered}$ <h2>STEP 3: comparison between given equation and secØ equation</h2>

Then, we have that: