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xz_007 [3.2K]
3 years ago
7

Hello I had some math work if anyone who like to help , I can send you $ thank you

Mathematics
2 answers:
vlada-n [284]3 years ago
5 0
I can try to help. . . . . . . .
4vir4ik [10]3 years ago
3 0

Answer: i don't need the money but i can try to help you

Step-by-step explanation:

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What is the approximate value for the modal daily sales?
Aleksandr [31]

Answer:

Step-by-step explanation:

Hello!

<em>The table shows the daily sales (in $1000) of shopping mall for some randomly selected  days </em>

<em>Sales 1.1-1.5 1.6-2.0 2.1-2.5 2.6-3.0 3.1-3.5 3.6-4.0 4.1-4.5 </em>

<em>Days 18 27 31 40 56 55 23 </em>

<em>Use it to answer questions 13 and 14. </em>

<em>13. What is the approximate value for the modal daily sales? </em>

To determine the Mode of a data set arranged in a frequency table you have to identify the modal interval first, this is, the class interval in which the Mode is included. Remember, the Mode is the value with most observed frequency, so logically, the modal interval will be the one that has more absolute frequency. (in this example it will be the sales values that were observed for most days)

The modal interval is [3.1-3.5]

Now using the following formula you can calculate the Mode:

Md= Li + c[\frac{(f_{max}-f_{prev})}{(f_{max}-f_{prev})(f_{max}-f_{post})} ]

Li= Lower limit of the modal interval.

c= amplitude of modal interval.

fmax: absolute frequency of modal interval.

fprev: absolute frequency of the previous interval to the modal interval.

fpost: absolute frequency of the posterior interval to the modal interval.

Md= 3,100 + 400[\frac{(56-40)}{(56-40)+(56-55)} ]= 3,476.47

<em>A. $3,129.41 B. $2,629.41 C. $3,079.41 D. $3,123.53 </em>

Of all options the closest one to the estimated mode is A.

<em>14. The approximate median daily sales is … </em>

To calculate the median you have to identify its position first:

For even samples: PosMe= n/2= 250/2= 125

Now, by looking at the cumulative absolute frequencies of the intervals you identify which one contains the observation 125.

F(1)= 18

F(2)= 18+27= 45

F(3)= 45 + 31= 76

F(4)= 76 + 40= 116

F(5)= 116 + 56= 172 ⇒ The 125th observation is in the fifth interval [3.1-3.5]

Me= Li + c[\frac{PosMe-F_{i-1}}{f_i} ]

Li: Lower limit of the median interval.

c: Amplitude of the interval

PosMe: position of the median

F(i-1)= accumulated absolute frequency until the previous interval

fi= simple absolute frequency of the median interval.

Me= 3,100+400[\frac{125-116}{56} ]= 3164.29

<em>A. $3,130.36 B. $2,680.36 C. $3,180.36 D. $2,664</em>

Of all options the closest one to the estimated mode is C.

5 0
3 years ago
Can help me how<br>Macam mana... ​
Alborosie

Step-by-step explanation:

i)

2(x+2)=7

2x+4=7

2x=7-4

2x=3

x=3/2

ii)3x + y =8 , y=x

3x + x = 8

4x = 8

x = 2

8 0
3 years ago
Read 2 more answers
Rob can mop a warehouse in 10 hours. Maria can mop the same warehouse in 11 hours. Find how long it would take them if they work
Natali [406]
The answer would be 21 good luck hope you get it correct
4 0
3 years ago
Read 2 more answers
The perimeter of the triangular park shown on the right is 14x-5. What is the missing​ length?
Lina20 [59]

Answer:70

Step-by-step explanation:

7 0
3 years ago
Could someone explain and help
vichka [17]

Answer:

  80°

Step-by-step explanation:

The sum of the two angles (red and blue) is 145°, so you have ...

  (4x +5)° +(6x -10)° = 145°

  10x = 150 . . . . . . . . divide by °, add 5, simplify

  x = 15 . . . . . . . . . . . divide by 10

Then the measure of the angle of interest is ...

  m∠XMN = (6x -10)° = (6·15 -10)° = 80°

8 0
3 years ago
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