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2 years ago

How many 1/4 litre bottles can be filled from a jug containing 8 litres of water?

Mathematics

2 answers:

Ivahew [28]2 years ago

7 0

Answer:

easy...

Step-by-step explanation:

8 divided by 1/4 is 32

so flip that around...

1/4 * 32 is 8

frosja888 [35]2 years ago

6 0

Answer:

32 bottles

Step-by-step explanation:

In this scenario, we have to divide 8 by 1/4 to see how many of those 1/4-liter bottles can be filled with 8 liters of water. So, let's go ahead and see how this looks mathematically, then we'll start simplifying:

$\frac{8}{1}$ ÷ $\frac{1}{4}$

Dividing by a fraction is the same as multiplying by that same fraction's reciprocal, so we can rearrange our math to make things easier.

$\frac{8}{1}$ × $\frac{4}{1}$

Now, we can multiply the numerators and the denominators.

$\frac{8}{1}$ × $\frac{4}{1}$ $= \frac{32}{1} =32$

So 32 of those 1/4 liter bottles can be filled from a jug containing 8 liters of water. Hopefully this was helpful! If anything was confusing or didn't make sense, let me know so I can make things clearer. :)

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Help!!!!!!!!!!! Solve for x x+11+8x=29 Explain how you got the answer please!

dolphi86 [110]

X + 11 + 8x = 29. We need to solve for x.
First, on the left side, you have "x" and "8x": You can always add 2 numbers with the same variable, so you have 1 number: x + 8x = 1x + 8x = (1+8)x = 9x

So we get:
9x + 11 = 29

Now subtract 11 from both sides (You can't do any operation if you don't do it both sides), so you can get the variable alone on the left side, and the numbers on the right side:
9x + 11 = 29
9x + 11 - 11 = 29 - 11
9x = 18

Now divide both sides by 9, so you can transform the coefficient of x to one, and have the numeric value of x on the right side:
9x = 18
(9x)/9 = 18/9
x = 2

So x+11+8x = 29 for x = 2.

You can recheck your answer (very important):
x + 11 + 8x = 2 + 11 + 8*2 = 2 + 11 + 16 = 13 + 16 = 29
The answer has been approved.

Hope this Helps! :)

8 0

3 years ago

Read 2 more answers

a red ball and 4 white ball are in a box if two balls are drawn without replacement ,what is the probability of getting a red ba

BARSIC [14]

The probability is 1/5 to get a red ball in 1st draw and a white ball in 2nd draw.

Step-by-step explanation:

There are 1 red ball and 4 white balls in a box.
The total number of balls in the box = 1 red + 4 white = 5 balls.

The two balls are drawn without replacement.

Drawing the first ball :

The first draw should be a red ball.

The probability to get a red ball = No.of red balls / Total balls in the box.

We know that, No. of red balls is 1 and total balls in the box is 5.

P(red ball) = 1/5

Drawing the second ball :

The second draw should be a white ball.

The probability to get white ball = No.of white balls / Total balls in the box.

We know that,

No. of white balls is 4.

The total balls in the box after the first draw will be 4 balls.

P(white ball) = 4/4

The probability of getting a red ball on the first drawn and a white ball on the second draw = P(red ball) × P(white ball)

⇒ (1/5) × (4/4)

⇒ 4/20

⇒ 1/5

Therefore, the probability is 1/5 to get a red ball in 1st draw and a white ball in 2nd draw.

3 0

2 years ago

A wheelchair ramp is 16 feet Long. The ramp sits up on a 2 foot platform. How far is it from the end of the ramp to the bottom o

il63 [147K]

Answer:

√254 feet

Step-by-step explanation:

This is basically a triangle, with a height of 2, and hypotenuse of 16.

Using the Pythagorean theorem (a^2+b^2=h^2) we can find the other side.

2^2+b^2=16^2

4+b^2=256

b^2=254

b=√254

3 0

2 years ago

What is 90-45-12. Plzzz

worty [1.4K]

Answer:

Step-by-step explanation:

45 is half of 90

So straight away go to 45-12

Hope this helps

-GoldenWolfX

6 0

3 years ago

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Annie is framing a photo with a length of 6 inches and a width of 4 inches. The distance from the edge of the photo to the edge

Ede4ka [16]

Answer:

Part a) The quadratic function is $4x^{2} +20x-39=0$

Part b) The value of x is $1.5\ in$

Part c) The photo and frame together are $7\ in$ wide

Step-by-step explanation:

Part a) Write a quadratic function to find the distance from the edge of the photo to the edge of the frame

Let

x----> the distance from the edge of the photo to the edge of the frame

we know that

$(6+2x)(4+2x)=63\\24+12x+8x+4x^{2}=63\\ 4x^{2} +20x+24-63=0\\4x^{2} +20x-39=0$

Part b) What is the value of x?

Solve the quadratic equation $4x^{2} +20x-39=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem

we have

$4x^{2} +20x-39=0$

$a=4\\b=20\\c=-39$

substitute in the formula

$x=\frac{-20(+/-)\sqrt{20^{2}-4(4)(-39)}} {2(4)}$

$x=\frac{-20(+/-)\sqrt{1,024}} {8}$

$x=\frac{-20(+/-)32} {8}$

$x=\frac{-20(+)32} {8}=1.5\ in$ -----> the solution

$x=\frac{-20(-)32} {8}=-6.5\ in$

Part c) How wide are the photo and frame together?

$(4+2x)=4+2(1.5)=7\ in$

5 0

3 years ago

How many 1/4 litre bottles can be filled from a jug containing 8 litres of water?​

How many 1/4 litre bottles can be filled from a jug containing 8 litres of water?