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2 years ago

15

Manny ran a total of 77 miles over the course of 7 track practices. How many track practices would it take for Manny to run 99 m

iles? Assume the relationship is directly proportional.

1 answer:

7nadin3 [17]2 years ago

7 0

Answer:

just add them up

Step-by-step explanation:

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Jenny's bakery sells carrot muffins at 2 dollars each. The electricity to run the over is over 120 dollars per day and the cost

g100num [7]

Answer:

200 muffins

Step-by-step explanation:

The selling price of each muffin = $2

The cost price of each muffin = $1.40

The price of electricity = $120

If the number of muffins that Jenny sells in a day is x, then, Jenny's total cost in a day is:

120 + (1.4 * x) = 120 + 1.4x

and the total sales earnings in a day for x muffins will be:

2 * x = 2x

To break even, the total costs in a day must equal to the total earnings. That is;

$2x = 120 + 1.4x$

Solving this:

$2x - 1.4x = 120\\\\\\0.6x = 120\\\\\\x = 120/0.6\\\\\\x = 200$

She must sell 200 muffins in a day to break even.

7 0

3 years ago

Find the value of x and the value of y

WARRIOR [948]

I’m pretty sure it’s b.

6 0

2 years ago

4x=17 math answer question

igor_vitrenko [27]

Answer: 4.25

divide 4 on both sides, and it should leave you with x = 4.25

your welcome :)

7 0

2 years ago

A contractor digs a hole for the basements of a new house that is 40 feet long and 10 1/2 feet deep. What is the width of the ho

34kurt

D. 15.5

40*10.5 = 420

6510/420 = 15.5

7 0

3 years ago

What is the equation, in standard form, of a parabola that models the values in the table?

love history [14]

Answer:

<u> $Y=4x^2+3x-6$ </u>

Step-by-step explanation:

For the standard form equation to model the values in the table, each value of x in the table should give the matching the y value when substituted into the equation. We will test each equation:

<u> $Y=3x^2+4x-6$ for (-2,4)</u>

$Y=3(-2)^2+4(-2)-6=3(4)+-8-6=12+-8-6=-2\\$

This does not give 4 as the answer and is not a solution.

<u> $Y=4x^2+3x-6$ for (-2,4)</u>

$Y=4(-2)^2+3(-2)-6=4(4)+-6-6=16+-6-6=-4\\$

This does give 4 as the answer and is a possible solution.

<u> $Y=4x^2-3x-6$ for (-2,4)</u>

$Y=4(-2)^2-3(-2)-6=4(4)+6-6=16+6-6=16\\$

This does not give 4 as the answer and is not a solution.

<u> $Y=-4x^2-3x-6$ for (-2,4)</u>

$Y=-4(-2)^2-3(-2)-6=-4(4)+6-6=-16+6-6=-16\\$

This does not give 4 as the answer and is not a solution.

The only possible solution is <u> $Y=4x^2+3x-6$ </u>

3 0

3 years ago