Answer:
Step-by-step explanation:
i) 1
ii) see attached
iii) as x goes from 0 to 2, y decreases parabolically from 1 to an acme at -3
iv) y = (x - 2)² - 3
v) -3 < t < 1
if t < -3 no intersection occurs between y = t and y = (x - 2)² - 3
if t = -3, y = t intersects the curve at only one point, (2, -3)
if -3 < t < 1 there exist two intersecting points with positive x values
if t = 1 there exist only one positive x value intersection as the other is at (0, 1) and 0 is neither positive nor negative.
if t > 1 there is one positive x value intersection and one negative x value intersection.
Answer:
B) All real numbers except 0 and integer multiples of 8π∕5
Step-by-step explanation:
Cotangent function:
The cotangent function is given by:
Domain:
All real values except those at which:
The sine is 0 for 0 and all integer multiples of
In this question:
, so the values outside the domain are 0 and the integer multiples of
. Then the correct answer is given by option b.
Answer:
<2 = 34degrees
Step-by-step explanation:
Find the diagram attached below:
First we need to get <1;
<1 + 74 = 180 (angle on a straight line)
<1 = 180 - 74
<1 = 106degrees
Also, <1 + <2 + 40 = 180 (sum of angle in a triangle)
106+<2 + 40 = 180
146 + <2 = 180
<2 = 180-146
<2 = 34degrees
