Let f(x) = x² + 6x²-x+ 5 then ,
number to be added be P
then,
f(x) = x² + 6x²-x+ 5 +P
According to the qn,
(x+3) is exactly divisible by zero then,
R=0
comparing .. we get a= -3
now by remainder theorm
R=f(a)
0=f(-3)
0=(-3)² + 6(-3)²-(-3)+ 5 + P
0= 9 + 54 + 3 + 5 + P
-71=P
therefore, -71 should be added.
Hope you understand
First, set 2x+7 equal to 3x-7 since they are the same angle due to the parallel lines.
2x+7=3x-7
x=14
Then, since 2x+7 and 12y+1 equals 180, put it together to find y:
(2x+7)+(12y+1)=180
(2(14)+7)+(12y+1)=180
12y+1=145
12y=144
y=12
So, x=14 and y=12. Your answer should be C!
If you know the base and area of the triangle, you can divide the base by 2, then divide that by the area to find the height. To find the height of an equilateral triangle, use the Pythagorean Theorem, a^2 + b^2 = c^2.
State the domain of the function<br>
(-3,-1,1,2,4)<br>
(-3,-1,1,2,3)<br>
{0, 1,3,4,5)<br>
{0, 1.4)
dmitriy555 [2]
Answer:
-4/4
Step-by-step explanation:
bc divison
I don't know what the first two blanks are asking for, but the last one should be Alternate Exterior Angles Property of Congruence (AEAPC).
