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Korolek [52]
3 years ago
8

How do I solve the system of equations x^2 +y=0 and x^2+y=0? I have to use substitution

Mathematics
1 answer:
Wittaler [7]3 years ago
5 0
Equations
• x² + y = 0 ... (1)
• x² - 4x - y = 0 ... (2)

Answer -> (x, y) = (2, -4)

Step-by-step solution:

From equation 2,
-> y = x² - 4x ... (3)

• Substitute y into equation 1

-> x² + (x² - 4x) = 0
-> 2x² - 4x = 0
-> 2x² = 4x
-> x²/x = 4/2
-> x = 2

• Put x = 2 in equation 3

-> y = (2)² - 4(2)
-> y = 4 - 8
-> y = -4
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This is a stupid question.  The teacher who asked this needs to go back to school.

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They don't want the correct answer.  They want you to factor this expression.  We'll do it, but don't believe for a second this factoring somehow constrains the possible dimensions of some rectangle.

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