Question

How do I solve the system of equations x^2 +y=0 and x^2+y=0? I have to use substitution

Answer 1

Equations
• x² + y = 0 ... (1)
• x² - 4x - y = 0 ... (2)

Answer -> (x, y) = (2, -4)

Step-by-step solution:

From equation 2,
-> y = x² - 4x ... (3)

• Substitute y into equation 1

-> x² + (x² - 4x) = 0
-> 2x² - 4x = 0
-> 2x² = 4x
-> x²/x = 4/2
-> x = 2

• Put x = 2 in equation 3

-> y = (2)² - 4(2)
-> y = 4 - 8
-> y = -4