W = f d, solve for d

Mathematics

1 answer:

zvonat [6]3 years ago

7 0

D=W over F j3jejensbshhsnsnsnjs

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natima [27]

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3 years ago

add the term that makes the given expression into a perfect square. write the result as the square of a bracketed expression c s

Molodets [167]

<h2>Perfect Squares</h2>

Perfect square formula/rules:

$a^2+2ab+b^2=(a+b)^2$
$a^2-2ab+b^2=(a-b)^2$

Trinomials are often organized like $ax^2+bx+c$ .

The <em>b</em> value in this case is <em>c</em>, and it will always equal the square of half of the <em>b</em> value.

Perfect square trinomial: $ax^2+bx+(\dfrac{b}{2})^2$
or $ax^2-bx+(\dfrac{b}{2})^2$

<h2>Solving the Question</h2>

We're given:

$c^2-4c$

In a trinomial, we're given the $ax^2$ and $bx$ values. <em>a</em> in this case is 1 and <em>b</em> in this case is 4. To find the third value by dividing 4 by 2 and squaring the quotient:

4 ÷ 2 = 2
2² = 4

Therefore, the term that we can add is + 4.

$c^2-4c+4$

To write this as the square of a bracketed expression, we can follow the rule $a^2-2ab+b^2=(a-b)^2$ :

$(c-2)^2$

<h2>Answer</h2>

$c^2-4c+4$

$(c-2)^2$

4 0

2 years ago

This is a radical equation

riadik2000 [5.3K]

To solve for p, square both sides and move the equation to one side is equal to zero. Then factor. I chose -2 and -5 because -2 x -5 = 10 and -2 + -5 = -7. After factoring, solve p-5=0 and p-2=0. When one of those equals zero then the equation (p-5)(p-2)=0 is true.