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Nataly [62]
3 years ago
13

W = f d, solve for d

Mathematics
1 answer:
zvonat [6]3 years ago
7 0
D=W over F j3jejensbshhsnsnsnjs
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Andrew's bowling scores are approximately normally distributed with mean 130 and standard deviation 21, while Pam's scores are n
White raven [17]

Answer:

2

Step-by-step explanation:

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3 years ago
What is the answer to 198=-4x+2(-6x+3)
liq [111]

Answer:  x = 12

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7 0
3 years ago
24 cm ,18cm ,c <br> We are looking for c
Ierofanga [76]

Step-by-step explanation:

we can find the value of c by Pythagoras theorem

according to Pythagoras theorem

h² = a² + b²

where

h = hypotenuse (i.e. longest side of a right angled triangle)

a = side

b = base

so, we have to find h or hypotenuse here

h² = (24)² + (18)²

h = 576 + 324 = 900

h² = √900 = 30

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therefore, value of c is 30.

Hope this answer helps you dear!

3 0
2 years ago
What is the first step in the following equation?<br> 28 = -12 - 4x
zmey [24]

Answer:

4x =  - 12 - 28 \\ 4x =  - 40 \\ x =  - 10

6 0
3 years ago
Read 2 more answers
A fish tank contains 16 goldfish and 24 guppies. If you randomly select 2 fish, what is the probability that they are both goldf
morpeh [17]
Hello, Shakiya214!

If a fish tank contains 16 goldfish and 24 guppies, then we can deduce that the total number of fish in the tank is: 16 + 24 = 40 fish.
If there are 16 goldfish in the tank, then of the 40 total fish, we have a probability of 16/40.

To illustrate this idea, suppose we had n fish in the tank (a guppies and b goldfish). The probability of selecting any fish is 100% (because there are only fish in the tank). If we had to select the goldfish, we could choose them like this:

p₁, p₂, p₃, p₄ ... pₐ

We could choose any one of these fish twice. This leaves us with: 16/40
Now, if they were NOT replaced, we could simply do it again. Except this time, we can only choose 15 out of the remaining 39 goldfish, leaving us with a probability of: (16/40)(15/39) = 240/1560 = 6/39 = 2/13
4 0
3 years ago
Read 2 more answers
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