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Hitman42 [59]
3 years ago
7

Find the sum of the measures of the angles of the figure

Mathematics
1 answer:
Lisa [10]3 years ago
7 0

Answer:

The figure is missing

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Let f be a functions of degree 4 whose coefficients are real numbers: two of its zeros are - 3 and 4 - i. Explain why one of the
kvasek [131]

Answer:

Step-by-step explanation:

We have the following theorem, if f is a polynomial with real coefficients, we can factor it completely in factors of the degree at most 2.

Consider first a polynomial of degree two, hence it is a polynomial of the form ax^2+bx+c. The cuadratic formula tells us that the solutions are of the form

x = \frac{-b\pm \sqrt[]{b^2-4ac}}{2a}.

Note that square root, over the reals, tells us that the are only real solutions if b^2-4ac \geq 0. If that is not the case, say it's negative, the solution are complex. Then, the solutions are of the form

x = \frac{-b \pm i \sqrt[]{4ac-b^2}}{2a}. NOte that this means that if we have a complex number of the form a+bi that is a solution, then the number a-bi (who is called the complex conjugate) is also a solution.

Recall that when we have a polynomial f(x) whose a zero is the number c, then we can factor f as follows f(x) = (x-c) * p(x) where p(x) is another polynomial of lesser degree .

So far, we know that -3 and 4-i are zeros of the function f. Note that we are missing two zeros. But, since complex numbers are zeros of polynomial only by pairs (that is the number and its conjugate are zeros), then, we must have that one of the missing 2 zeros is a real number. We have 4-i as a zero, then, its complex conjugate must be also a zero, i.e 4+i is a zero.

8 0
3 years ago
Geometry draw a quadrilateral with the verteices r(-3,-1), s(-1,0),t
agasfer [191]
This is an incomplete problem
3 0
3 years ago
– 2y – 10 = x<br> - 10x - y = -14
fredd [130]

Answer:

hey there guys ^^

Step-by-step explanation:

5 0
3 years ago
Solve the equation for m:<br><br> m/5 = 60
alex41 [277]

Answer:

m = 300

Step-by-step explanation:

m/5 = 60

multiply both sides of the equation by 5

m = 60 * 5 = 300

3 0
3 years ago
Read 2 more answers
A package contains 12 resistors, 3 of which are defective. If 4 are selected, find the probability of getting
s344n2d4d5 [400]

Answer:

Incomplete question, but I gave a primer on the hypergeometric distribution, which is used to solve this question, so just the formula has to be applied to find the desired probabilities.

Step-by-step explanation:

The resistors are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

12 resistors, which means that N = 12

3 defective, which means that k = 3

4 are selected, which means that n = 4

To find an specific probability, that is, of x defectives:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = x) = h(x,12,4,3) = \frac{C_{3,x}*C_{9,4-x}}{C_{12,4}}

7 0
3 years ago
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