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mestny [16]
3 years ago
12

I need help with this problem ASAP!

Mathematics
1 answer:
denpristay [2]3 years ago
7 0

Answer:

Get = Scammed

Step-by-step explanation:

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Kathy starts with a number. She adds 3 to her number then doubles the result. Finally she subtract 7. If she ended with 9 what n
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if she has 9, add 7. you have 16. divide it by half, 8. subtract 3 and you get 5.

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Help please i need this done by tmr !
Nataly [62]

Answer:

see explanation

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

sum the 3 angles and equate to 180

5x + 7 + 4x + 2 + 90 = 180 , that is

9x + 99 = 180 ( subtract 99 from both sides )

9x = 81 ( divide both sides by 9 )

x = 9

Then

∠ ACB = 4x + 2 = 4(9) + 2 = 36 + 2 = 38°

∠ BAC = 5x + 7 = 5(9) + 7 = 45 + 7 = 52°

-----------------------------------------------------------------------

Since the triangles are congruent then corresponding angles are congruent , so

∠ B = ∠ E

6x + 10 = 70 ( subtract 10 from both sides )

6x = 60 ( divide both sides by 6 )

x = 10

5 0
3 years ago
Let \[f(x) = \frac{3x - 7}{x + 1}.\]find the range of $f$. give your answer as an interval.
ra1l [238]
Hello :
let : y=  \frac{3x-7}{x+1}
calculate : x ......x <span>≠ -1 
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yx+y =3x-7
yx-3x = -y-7
x(y-3) = -7-y
x =  \frac{y+7}{3-y}
the inverse function is : g(x) =  \frac{x+7}{3-x}
domain of : g  is the range of : f
as an interval : ]-∞: 3 <span>[</span>U ]3;+∞[

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3 years ago
A ray that contains a point that is equidistant from both sides of the angle. *
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<span>Consider a angle â BAC and the point D on its defector Assume that DB is perpendicular to AB and DC is perpendicular to AC. Lets prove DB and DC are congruent (that is point D is equidistant from sides of an angle â BAC Proof Consider triangles ΔADB and ΔADC Both are right angle, â ABD= â ACD=90 degree They have congruent acute angle â BAD and â CAD( since AD is angle bisector) They share hypotenuse AD therefore these right angle are congruent by two angle and sides and, therefore, their sides DB and DC are congruent too, as luing across congruent angles</span>
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3 years ago
X2 + y2 - 14x + 10y + 65 = 0 <br><br> will lie ENTIRELY in Quadrant
Afina-wow [57]
Rearranging to standard form 
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so the circle will be entirely in Quadrant 4.
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