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Phoenix [80]
2 years ago
7

I would really appreciate it if someone could help me with these last few problems

Mathematics
1 answer:
lorasvet [3.4K]2 years ago
7 0

Answer:

Ouestion 5 answers

1)8.5

2)150

3)8

4)15

Step-by-step explanation:

You might be interested in
Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1
alexandr1967 [171]

Answer:

a) \simeq 0.3012   b) \simeq 0.0494 c) \simeq 0.2438

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, \frac{1.2}{4}

= 0.3 collisions per  month

So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

          P(X =x) = \frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}


                                                           for x ∈ N ∪ {0}

                       =  0 otherwise --------------------------------------(1)

here, \lambda = 0.3 collision / month

No collision over a 4 month period means no collision per month or X =0

Putting X = 0 in (1) we get,

         P(X = 0) = \frac{e^{-0.3}\times {\0.3}^{0}}{0!}


                      \simeq 0.7408182207 ------------------------------------(2)

Now, since we are calculating  this for 4 months,

so, P(No collision in 4 month period)

     =0.7408182207^{4}

     \simeq 0.3012  -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

Putting X =1 in (1) we get,

           P(X =1) = \frac{e^{-0.3}\times {\0.3}^{1}}{1!}


                      \simeq 0.2222454662 ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

                =0.2222454662^{2}

                \simeq 0.0494 -----------------------------------------(5)

1 collision in 6 months period means

                                \frac{1}{6} collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6]  (which is to be estimated)

=\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

\simeq 0.6543894283-------------------------------------------(6)

So,

P(1  collision in 6 month period)

  =  0.6543894283^{6}

   \simeq 0.0785267444 ------------------------------------------------(7)

So,

P(No collision in 6 months period)

  = (P(X =0)^{6}

   \simeq 0.1652988882 ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

\simeq  0.2438 ---------------------------------------------(9)          

7 0
3 years ago
In order to determine the average price of hotel rooms in Atlanta, a sample of 64 hotels was selected. It was determined that th
deff fn [24]

Answer:

The decision rule is  

Fail to reject the null hypothesis

The conclusion is  

There is no sufficient evidence to show that the average room price is significantly different from $108.50

Step-by-step explanation:

From the question we are told that

   The sample size is  n = 64

    The average price is  \= x  = \$ 112

    The population standard deviation is  \sigma  = \$ 16

     The level of significance is  \alpha  = 0.05

    The population mean is  \mu = \$ 108.5

The null hypothesis is  H_o :  \mu = 108.50

The alternative hypothesis is  H_a  :  \mu \ne  108.50

Generally the test statistics is mathematically represented as

       z = \frac{\= x - \mu }{ \frac{ \sigma}{\sqrt{n} } }

=>    z = \frac{112 - 108.50 }{ \frac{ 16}{\sqrt{64} } }  

=>    z = 1.75

From the z table  the area under the normal curve to the left corresponding to  1.75  is  

       P( Z >  1.75) = 0.040059

Generally  p-value is mathematically represented as

        p-value = 2 * P( Z >  1.75)

=>     p-value = 2 * 0.040059

=>     p-value = 0.08012

From the values obtained we see that  p-value  > \alpha hence

The decision rule is  

Fail to reject the null hypothesis

The conclusion is  

There is no sufficient evidence to show that the average room price is significantly different from $108.50

 

3 0
3 years ago
What is the surface area of s sphere with a radius of 4ft
erik [133]
The formula you use to find the surface area of a sphere is A=4 π r^2
4×π = 12.5663706143
r = 4
4^2 = 16
12.5663706143 × 16 = 201.061929829
Final answer: the surface area is about 201 ft.
8 0
3 years ago
Workout the median 6266 6626 6622 6226 6662 6222 7466
sasho [114]

Answer:

Step-by-step explanation:

the median would be 2,2 just the middle number/numbers if it has 1 # thats the median if it has 2 thats still the median

7 0
3 years ago
Read 2 more answers
What is the largest perimeter possible for a rectangle with positive whole number dimensions and an area of 40 cm?
Vladimir79 [104]

Answer:

C, 82 cm

Step-by-step explanation:

If the area of a rectangle is it's length times it's width and for the problem, it's maximum area must be 40cm than 40x1 would offer the largest perimeter with the smallest area respectively totalling at 82 cm.

8 0
3 years ago
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