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balu736 [363]
2 years ago
8

Marcie bought a 59-foot roll of packing tape. She used two 8 5/6 foot lengths.How much tape is left on the roll?

Mathematics
1 answer:
madreJ [45]2 years ago
3 0
Marcie has 41 1/3 feet of packing tape left.

8 5/6 times 2 makes 17 2/3. 59 minus 17 2/3 equals 41 1/3.
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What is the approximate value for the modal daily sales?
Aleksandr [31]

Answer:

Step-by-step explanation:

Hello!

<em>The table shows the daily sales (in $1000) of shopping mall for some randomly selected  days </em>

<em>Sales 1.1-1.5 1.6-2.0 2.1-2.5 2.6-3.0 3.1-3.5 3.6-4.0 4.1-4.5 </em>

<em>Days 18 27 31 40 56 55 23 </em>

<em>Use it to answer questions 13 and 14. </em>

<em>13. What is the approximate value for the modal daily sales? </em>

To determine the Mode of a data set arranged in a frequency table you have to identify the modal interval first, this is, the class interval in which the Mode is included. Remember, the Mode is the value with most observed frequency, so logically, the modal interval will be the one that has more absolute frequency. (in this example it will be the sales values that were observed for most days)

The modal interval is [3.1-3.5]

Now using the following formula you can calculate the Mode:

Md= Li + c[\frac{(f_{max}-f_{prev})}{(f_{max}-f_{prev})(f_{max}-f_{post})} ]

Li= Lower limit of the modal interval.

c= amplitude of modal interval.

fmax: absolute frequency of modal interval.

fprev: absolute frequency of the previous interval to the modal interval.

fpost: absolute frequency of the posterior interval to the modal interval.

Md= 3,100 + 400[\frac{(56-40)}{(56-40)+(56-55)} ]= 3,476.47

<em>A. $3,129.41 B. $2,629.41 C. $3,079.41 D. $3,123.53 </em>

Of all options the closest one to the estimated mode is A.

<em>14. The approximate median daily sales is … </em>

To calculate the median you have to identify its position first:

For even samples: PosMe= n/2= 250/2= 125

Now, by looking at the cumulative absolute frequencies of the intervals you identify which one contains the observation 125.

F(1)= 18

F(2)= 18+27= 45

F(3)= 45 + 31= 76

F(4)= 76 + 40= 116

F(5)= 116 + 56= 172 ⇒ The 125th observation is in the fifth interval [3.1-3.5]

Me= Li + c[\frac{PosMe-F_{i-1}}{f_i} ]

Li: Lower limit of the median interval.

c: Amplitude of the interval

PosMe: position of the median

F(i-1)= accumulated absolute frequency until the previous interval

fi= simple absolute frequency of the median interval.

Me= 3,100+400[\frac{125-116}{56} ]= 3164.29

<em>A. $3,130.36 B. $2,680.36 C. $3,180.36 D. $2,664</em>

Of all options the closest one to the estimated mode is C.

5 0
3 years ago
The diameter of a circle is 14 inches. Find the circumstance and area use 22/7
s344n2d4d5 [400]

Answer:

Circumference= 44 in

Area= 154 in²

Step-by-step explanation:

\boxed{circumference \: of \: circle = 2\pi  r}

Radius

= diameter ÷2

= 14 ÷2

= 7 in

Circumference of circle

= 2( \frac{22}{7} )(7)

= 44 in

\boxed{area \: of \: circle = \pi {r}^{2} }

Area of circle

=  \frac{22}{7} ( {7}^{2} )

= 154 in²

3 0
3 years ago
Please help mee I don't understand this for some reasonnnn!!
Vesnalui [34]

Answer:

bivariate data

Scatter plot

positive assossiation

negitive assossiation

linear assocciation

nonlinear assocciaton

clustering

outlier

Step-by-step explanation:

7 0
2 years ago
If the price of a car decreases by 12%, the price would be 26,880. What is the original price
melomori [17]

Answer:

26,880/12%=224000

Step-by-step explanation:

4 0
3 years ago
In ΔQRS, the measure of ∠S=90°, the measure of ∠Q=29°, and SQ = 5 feet. Find the length of QR to the nearest tenth of a foot.
goldfiish [28.3K]

Answer:

2.8 feet

Step-by-step explanation:

tan(29)=x/5

5tan(29)=x

2.8=x

8 0
2 years ago
Read 2 more answers
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