Part A:
Given a square with sides 6 and x + 4. Also, given a rectangle with sides 2 and 3x + 4
The perimeter of the square is given by 4(x + 4) = 4x + 16
The area of the rectangle is given by 2(2) + 2(3x + 4) = 4 + 6x + 8 = 6x + 12
For the perimeters to be the same
4x + 16 = 6x + 12
4x - 6x = 12 - 16
-2x = -4
x = -4 / -2 = 2
The value of x that makes the <span>perimeters of the quadrilaterals the same is 2.
Part B:
The area of the square is given by

The area of the rectangle is given by 2(3x + 4) = 6x + 8
For the areas to be the same

Thus, there is no real value of x for which the area of the quadrilaterals will be the same.
</span>
This is quite easy, but anyway:
In order, they are
3, 4, 4, 5, 5, 5, 5, 7, 7
7 - 3 = 4
4 would be the range
X=2m-nx-4
If you need help just ask me.
Answer:
it divides by five
Step-by-step explanation:
500/5=100
100/5=20
20/5=4
4/5=0.8!
Brainliest pls