a = 2πr² + 2πrh
a - 2πr² = 2πrh
(a - 2πr²)/2πr = 2πrh/2πr
h = (a - 2πr²)/2πr
<em><u>Question:</u></em>
One dollar is worth 3 1/2 kruneros. What is the value of 43 3/4 kruneros?
<em><u>Answer:</u></em>
The value of
kruneros is 12.5 dollars
<em><u>Solution:</u></em>
Given that,
Dollar is worth three and 3 1/2 kruneros
Which means,
![1 \text{ dollar } = 3\frac{1}{2} \text{ kruneros }\\\\1 \text{ dollar } = 3.5 \text{ kruneros }](https://tex.z-dn.net/?f=1%20%5Ctext%7B%20dollar%20%7D%20%3D%203%5Cfrac%7B1%7D%7B2%7D%20%5Ctext%7B%20kruneros%20%7D%5C%5C%5C%5C1%20%5Ctext%7B%20dollar%20%7D%20%3D%203.5%20%5Ctext%7B%20kruneros%20%7D)
We have to find the value of
kruneros
Let us convert the mixed fractions to improper fractions
Multiply the whole number part by the fraction's denominator.
Add that to the numerator.
Then write the result on top of the denominator.
![43\frac{3}{4} = \frac{43 \times 4 + 3}{4} = \frac{175}{4} = 43.75](https://tex.z-dn.net/?f=43%5Cfrac%7B3%7D%7B4%7D%20%3D%20%5Cfrac%7B43%20%5Ctimes%204%20%2B%203%7D%7B4%7D%20%3D%20%5Cfrac%7B175%7D%7B4%7D%20%3D%2043.75)
So we have to find the value of 43.75 kruneros
Let "x" be the value of 43.75 kruneros
Then,
1 dollar = 3.5 kruneros
x dollar = 43.75 kruneros
This forms a proportion and we can solve the sum by cross multiply
![1 \times 43.75 = x \times 3.5\\\\x = \frac{43.75}{3.5}\\\\x = 12.5](https://tex.z-dn.net/?f=1%20%5Ctimes%2043.75%20%3D%20x%20%5Ctimes%203.5%5C%5C%5C%5Cx%20%3D%20%5Cfrac%7B43.75%7D%7B3.5%7D%5C%5C%5C%5Cx%20%3D%2012.5)
Thus value of
kruneros is 12.5 dollars
Answer:
yES 2:3
Step-by-step explanation:
The sides are the same length
Answer:
if youre trying to solve by finding x then x = 5 and y = 2
Step-by-step explanation:
Answer:
<h3>Q 1</h3>
<u>Sum of interior angles of a pentagon:</u>
- 4x + 60 = 180(5 - 2)
- 4x + 60 = 540
- 4x = 480
- x = 120
<h3>Q 6</h3>
<u>Midsegment is half of the sum of the bases:</u>
- (2n - 2 + 4n + 6)/2 = n + 12
- (6n + 4)/2 = n + 12
- 3n + 2 = n + 12
- 2n = 10
- n = 5
<u>Midsegment is:</u>
Correct choice is D
<h3>Q 3</h3>
- m∠1 = 90 as diagonals are perpendicular
- m∠2 = 41 as alternate interior angles
<u>∠3 is complementary with ∠2:</u>
None of the choices is correct