Answer:
-9 may be the right answer
Answer:
(x + 1 s 1) n (x + 12 1)
(x +1<1) n (x + 1 > 1)
Step-by-step explanation:
Just simplify each the statements.
Then compare and and see if the statements are contradictory and therefore FALSE, if so, then there is no solution.
(x + 1<-1) n (x + 1< 1)
(x <-2) n (x < 0) which is true, so there is a solution.
(x + 1 s 1) n (x + 12 1)
this doesn't make sense so there is no solution.
(x +1<1) n (x + 1 > 1)
(x < 0) n (x > 0)
This is not possible, the statements are contradictory and therefore FALSE, so there is no solution.
Can you tell me what they are asking you to do
This is so I know if you understand the question
The values that make this statement falser are any in which a and b do not have the same sign.
For instance, if a was equal to 3 and b was equal to -3 than see the results.
|a+b|=
|3+-3|=
|0|= 0
Then see the next equation with the same selections
|a|+|b|
|3|+|-3|
3 + 3 = 6
And this would be true no matter which is the negative, as long as there is one negative and one positive.
I cannot see the picture to good
