12: twelve
1 rod(10 blocks)
2 cubes(2 singles blocks)
A = (h * b) / 2
A = 200
h = 4b
200 = (b(4b) / 2
200 * 2 = b * 4b
400 = 4b^2
400 / 4 = b^2
100 = b^2
sqrt 100 = b
10 = b ..... base is 10 cm
h = 4b
h = 4(10)
h = 40 <=== height is 40 cm
Given that,
An equation : -9c² +2c +3 = 0
To find,
Find the value of x.
Solution,
We have, -9c² +2c +3 = 0
We can solve it using the formula as follows :
![x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=x%3D%5Cdfrac%7B-b%5Cpm%20%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D)
Here, a = -9, b = 2 and c =3
Put the values,
![c=\dfrac{-2\pm \sqrt{(2)^2-4(-9)(3)}}{2(-9)}\\\\c=\dfrac{-2+\sqrt{(2)^{2}-4(-9)(3)}}{2(-9)}, \dfrac{-2-\sqrt{(2)^{2}-4(-9)(3)}}{2(-9)}\\\\c=-0.47, 0.69](https://tex.z-dn.net/?f=c%3D%5Cdfrac%7B-2%5Cpm%20%5Csqrt%7B%282%29%5E2-4%28-9%29%283%29%7D%7D%7B2%28-9%29%7D%5C%5C%5C%5Cc%3D%5Cdfrac%7B-2%2B%5Csqrt%7B%282%29%5E%7B2%7D-4%28-9%29%283%29%7D%7D%7B2%28-9%29%7D%2C%20%5Cdfrac%7B-2-%5Csqrt%7B%282%29%5E%7B2%7D-4%28-9%29%283%29%7D%7D%7B2%28-9%29%7D%5C%5C%5C%5Cc%3D-0.47%2C%200.69)
So, the solution are -0.47 and 0.69.
Answer:
40
Step-by-step explanation:
2+2 = 4
4+4 = 8
8+32= 40