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Anni [7]
3 years ago
5

Write an equation for the nth term of the arithmetic sequence. Then find a30 6, 12, 18, 24,

Mathematics
1 answer:
Gelneren [198K]3 years ago
8 0

Answer:

1. 6n

2. 6×30=180

Step-by-step explanation:

180 is the 30th term

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Which corresponds to the perimeter of triangle ABC?
____ [38]

Answer:

The answer to your question is: letter C

Step-by-step explanation:

Data

A (-5 , -1)

B (-2, 3)

C (6, -3)

Perimeter = ?

Formula

d = \sqrt{(x2 - x1)^{2} + (y2 - y1)^{2} }

distance AB      d = \sqrt{(-2 + 5)^{2} + (3 + 1)^{2} }

                         d = \sqrt{(3)^{2} + (4)^{2} }

                         d = \sqrt{(9 + (16) }

                                 d = \sqrt{25}

                                        d = 5

Distance BC    d = \sqrt{(-3 - 3)^{2} + (6 + 2)^{2} }

                         d = \sqrt{(-6)^{2} + (8)^{2} }

                         d = \sqrt{36 + 64}                    

                         d = \sqrt{100}

                                d = 10

Distance AC     d = \sqrt{(-3 + 1)^{2} + (6 + 5)^{2} }

                         d = \sqrt{(-2)^{2} + (11)^{2} }

                         d = \sqrt{4 + 121}

                         d = \sqrt{125}

                                d = 11.2

Perimeter = 5 + 10 + 11.2

                = 15 + \sqrt{125}

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4 years ago
(1 point) an open box is to be made from a flat piece of material 12 inches long and 5 inches wide by cutting equal squares of l
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The answer stays in school kids I'm not really sure on the answer to ask your teacher.
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Brainlist<br> Write all the factors of .49<br> Use commas to separate them.
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.7 and 1 that's all.
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4 years ago
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Graph the line and the circle (x-1)²+(y-2)²=2² and y=2x+2.
Temka [501]

Answer:

The graph of the line and the circle is in the attachment.

Step-by-step explanation:

In order to graph the circle, you have to use the circle equation formula to obtain the center and the radius.

(x-xo)² + (y-yo)² = r²

where the point (xo,yo) is the center and r is the radius.

Using the given formula, the center is:

xo=1, yo=2

(1,2)

And the radius is:

r=2

Now you have to graph the point (1,2) and draw a circle centered at that point, with a distance of 2 from the center.

To obtain the exact values of the intersection of the circle with the x-axis you have to replace y=0 in the equation and solve it for x. For the points of intersection with the y-axis you have to replace x=0 in the equation and solve it for y.

-For x=0, solving for y:

(0-1)²+(y-2)²=2²

1+(y-2)²=4

(y-2)²= 3

Applying the squareroot both sides

y-2 = ± √3

y1= -√3 +2

y2= √3 +2

P1(0, -√3 +2) and P2(0, √3 +2)

-For y=0

(x-1)²+(0-2)²=2²

(x-1)² + 4 = 4

(x-1)² = 0

Applying the squareroot both sides:

x-1 = √0

x-1=0

x=1

P3 (1,0)

In order to graph the linear equation, you have to obtain the intersection with the x-axis replacing y=0 in the equation and the intersection with the y-axis replacing x=0 in the equation. That way, you obtain two point of the line and then you have to trace the line containing those points.

-For x=0

y=2(0)+2 =2

P1 (0,2)

-For y=0

0= 2x+2

Adding -2 both sides

2x= -2

Dividing by 2 both sides

x= -1

P2(-1,0)

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velikii [3]
0.5,0.55,0.005,0.505 is my answer



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8 0
3 years ago
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