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VARVARA [1.3K]
2 years ago
15

Write an equation representing how much Tristan paid.

Mathematics
1 answer:
slavikrds [6]2 years ago
4 0

Answer:

10000

Step-by-step explanation:

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What does the expression 3x+4y equal
enot [183]
That expression can’t be simplified and the answer is unknown. Finding what 3x+4y is impossible unless more information is provided.
7 0
3 years ago
In the expansion of (1/ax +2ax^2)^5 the coefficient of x is five. Find the value of the constant a.
DedPeter [7]

Answer:

80x⁴

Step-by-step explanation:

(\frac{1}{ax} + 2ax^2)^5 = 5C_0(\frac{1}{ax})^5(2ax^2)^0 + 5C_1(\frac{1}{ax})^4(2ax^2)^1 + 5C_2(\frac{1}{ax})^3 (2ax^2)^2

                           + 5C_3 (\frac{1}{ax})^2(2ax^2)^3 + 5C_4(\frac{1}{ax})^1(2ax^2)^4 + 5C_5(\frac{1}{ax})^0(2ax^2)^5

5C_0(\frac{1}{ax})^5(2ax^2)^0  =1 \times (\frac{1}{ax})^5 \times 1 = \frac{1}{a^5x^5}\\\\5C_1(\frac{1}{ax})^4(2ax^2)^1  = 5 \times (\frac{1}{ax})^4 \times (2ax^2)^1 = 10 ax^2 \times \frac{1}{a^4x^4} = \frac{10}{a^3x^2}\\\\5C_2 (\frac{1}{ax})^3 (2ax^2)^2= 10 \times (\frac{1}{ax})^3 \times (2ax^2)^2 = 10 \times \frac{1}{a^3x^3} \times 4a^2x^4 = \frac{40x}{a}\\\\5C_3 (\frac{1}{ax})^2 (2ax^2)^3 = 10 \times (\frac{1}{ax})^2 \times (2ax^2)^3 = 10 \times \frac{1}{a^2x^2} \times 8a^3 x^6 = 80ax^4\\\\

5C_4(\frac{1}{ax})^1(2ax^2)^4 = 5 \times \frac{1}{ax} \times 16a^4x^8 = 80a^3x^7\\\\5C_5(\frac{1}{ax})^0(2ax^2)^5 = 1 \times 1 \times 32a^5x^{10}

The fourth term of the expansion has the constant a,

the coefficient of a is 80x⁴

6 0
3 years ago
The scatter plot below shows the number of animal cells Clara examined in a laboratory in different months: Plot ordered pairs 1
Paraphin [41]

The answer would be 340 and its correct because I did it!!

6 0
3 years ago
Read 2 more answers
Suppose we have a bottomless bag of 3 different kinds of balls: blue, green, and red. How many possibilities are there to choose
sleet_krkn [62]

The number of possibilities that are there to choose 3 balls is 6.

<h3>How to illustrate the information?</h3>

From the information, we have a bottomless bag of 3 different kinds of balls: blue, green, and red.

The number of possibilities that are there to choose 3 balls will be:

= 3!

= 3 × 2 × 1

= 6 possibilities.

Therefore, the number of possibilities that are there to choose 3 balls is 6.

Learn more about permutations on:

brainly.com/question/4658834

#SPJ1

6 0
1 year ago
Two different random samples were used to determine students’ favorite park in town. The results are below. Make at least two in
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Answer:

There going by 5's

Step-by-step explanation:

3 0
3 years ago
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