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3 years ago

What is 572 rounded to the nearest hundred?

Mathematics

2 answers:

juin [17]3 years ago

8 0

The answer is 600 because 70 is bigger than fifty

KiRa [710]3 years ago

8 0

600 any thing in hundredths is to 50 any thing over that or = is to the next hundredth and in tenths its to 5 and over and so on and so forth. hope it helps.

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Derive the equation of the parabola with a focus at (6,2) and a directrix of y=1

nydimaria [60]

Distance from focus to vertex=distance from vertex to directix

from (6,2) to y=1, the distance is 1
the focus is 1/2 higher than the vertex
vertex=(6,1.5)

for
(x-h)^2=4p(y-k)
vertex=(h,k)
p=distance from vertex to directix

vertex=(6,1.5)
ditance=0.5

(x-6)^2=4(0.5)(y-1.5)
(x-6)^2=2(y-1.5) is the equation
or
y=0.5x^2-6x+19.5 or
y=0.5(x-6)^2+1.5

7 0

3 years ago

Read 2 more answers

Suppose a kite has two congruent angles of 100°. Of the remaining angles, one is four times larger than the other. What is the m

Pani-rosa [81]

Answer:

The measure of the largest angle in the kite is 128 degrees

Step-by-step explanation:

we know that

The sum of the interior angles in any quadrilateral must be equal to 360 degrees

A kite is a quadrilateral

Let

A,B,C and D the measure of the interior angles

$A+B+C+D=360^o$

we have that

$A=B=100^o$

substitute

$100^o+100^o+C+D=360^o$

$C+D=160^o$ ----> equation A

Remember that

one is four times larger than the other

$C=4D$ ----> equation B

substitute equation B in equation A

$4D+D=160$

solve for D

$5D=160\\D=32^o$

Find the measure of angle C

$C=4(32)=128^o$

therefore

The measure of the largest angle in the kite is 128 degrees

5 0

3 years ago

Hey can you solve for both please

Strike441 [17]

Y=4 on the first one
A=92 on the second one

6 0

2 years ago

F(x)

mina [271]

a) Since both limits are distinct and do not exist, we conclude that x = - 1 is not part of the domain of the rational function.

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<h3>How to determine whether a limit exists or not</h3>

According to theory of limits, a function f(x) exists for x = a if and only if $\lim_{x\to a^{-}} f(x) = \lim_{x \to a^{+}} f(x)$ . This criterion is commonly used to prove continuity of functions.

Rational functions are not continuous for all value of x, as there are x-values that make denominator equal to 0. Based on the figure given below, we have the following lateral limits:

$\lim_{x \to -1^{-}} \frac{x}{x^{2}+x} = - \infty$