A)48
Explanation:
2^3 - 2^2 = 8 - 4 = 4
3^3 - 3^2 = 27 - 9 = 18
4^3 - 4^2 = 64 - 16 = 48
5^3 - 5^2 = 125 - 25 = 100
6^3 - 6^2 = 216 - 36 = 180
7^3 - 7^2 = 343 - 49 = 294
8^3 - 8^2 = 512 - 64 = 448
Note: The height of the room must be 3 m instead of 3 cm because 3 cm is too small and it cannot be the height of a room.
Given:
Perimeter of the floor of a room = 18 metre
Height of the room = 3 metre
To find:
The area of 4 walls of the room.
Solution:
We know that, the area of 4 walls of the room is the curved surface area of the cuboid room.
The curved surface area of the cuboid is

Where, h is height, l is length and b is breadth.
Perimeter of the rectangular base is 2(l+b). So,

Putting the given values, we get


Therefore, the area of 4 walls of the room is 54 sq. metres.
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x/5 = 6/15
15x = 30
x = 2
answer
x = 2 ft
y/10 = 6/15
15y = 60
y = 4
answer
y = 4 ft
Answer: 6*x*y
Step-by-step explanation:
u have to do 2*3 first