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3 years ago

6

Assume there are 20 people in a room, including you. You must shake hands with everyone else in the room. How many hands will yo

u shake

1 answer:

Oksanka [162]3 years ago

4 0

Answer:

19, I'm pretty sure?

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Farmer Ed has 800 meters of fencing, and wants to enclose a rectangular plot that borders on a river. If Farmer Ed does not fen

slega [8]

Answer:

Therefore the dimension of the plot is 400 m × 200 m.

The area of the plot is = 80000 m²

Step-by-step explanation:

Given that a farmer ED has 800 meters of fencing, and wants to enclose a rectangular plot that borders on a river.

Let the length of side along river side be L.

And the width of the plot be be W.

Since the farmer does not fence the river side.

So the length of fence = (L+2w) m

According to the problem,

(L+2w) = 800

⇒L=800 - 2w

Therefore the area of the plot is A = Length ×width

= (L×W) m²

=[(800-2W)W] m²

For maximum or minimum $\frac{dA}{dW}=0$

∴ A =(800-2W)W

⇒A = 800 W -2W²

Differentiating with respect to W

$\frac{dA}{dW} = 800 -2.(2W)$

$\Rightarrow \frac{dA}{dW} = 800 -4W$

For maximum or minimum $\frac{dA}{dW}=0$

$\Rightarrow 0 = 800 -4W$

$\Rightarrow W= \frac{800}{4}$

⇒W=200

Again,

$\frac{dA}{dW} = 800 -4W$

Again differentiating with respect to W

$\frac{d^2A}{dW^2}= -4$

$\therefore[ \frac{d^2A}{dW^2}]_{W=200}= -4$

When $\frac{d^2A}{dW^2}$ , then the area A is maximum at W=200.

When $\frac{d^2A}{dW^2}>0$ , then the area A is minimum at W=200.

Therefore at W= 200 m , the area of the plot maximum at W=200m

The length of the plot is L = [800- (2×200)] = 400 m

Therefore the dimension of the plot is 400 m × 200 m.

The area of the plot is = (400× 200) m²

= 80000 m²

3 0

3 years ago

Someone help me asap please.

zaharov [31]

15. x ≤ -24

x + 19 ≤ -5

x ≤ -24

16. z > -12

3z > -36

z > -12

17. 185 + c > 410; c > 225

18. C.

x - 6 ≥ 1

x ≥ 7

7 0

3 years ago

Calculate the approximate probability that at least 2 children have been diagnosed with ASD among the 200 selected children.

mixas84 [53]

Answer:

The approximate probability that at least 2 children have been diagnosed with ASD among the 200 selected children is

0.01 or 1%.

Step-by-step explanation:

Number of selected children = 200

The probability of no child been diagnosed with ASD = P(None) = 198/200 = 0.99

Therefore, the probability of at least two children been diagnosed with ASD = 1 - 0.99 = 0.01.

This is the same as:

If 2 children have been diagnosed with ASD,

therefore, the approximate probability that at least 2 children have been diagnosed is:

2/200 = 0.01. This value is equal to 1%.

The above are summed up in:

The probability of at least one = 1/200 = 0.05

Therefore, the probability of at least two = 0.05 * 2 = 0.01

b) Generally, to find the probability of at least one event happening, we calculate the probability of none and then subtract that result from 1. That is, P(at least one) = 1 – P(none). For two events happening, the sum of the probability of at least one in two places is deducted from 1 to get the probability of at least two.

4 0

3 years ago

PLEASE HELP ITS A TEST

xeze [42]

It is 180 because it rotates

5 0

2 years ago

Read 2 more answers

Pat is making 5 stools with circular seats that are each 12 inches in diameter. She wants to paint the tops of all the stools br

vivado [14]

Start by finding the area of one of the stools with this formula:
A=(3.14)(12)(12)
Then multiply that answer by five, since there are 5 stools.
Hope this helps :) good luck

6 0

3 years ago