Completing the square follows the principle of taking
![a x^{2} +bx+c](https://tex.z-dn.net/?f=a%20x%5E%7B2%7D%20%2Bbx%2Bc)
and converting it into
![(x+ \frac{b}{2})^2+d](https://tex.z-dn.net/?f=%28x%2B%20%5Cfrac%7Bb%7D%7B2%7D%29%5E2%2Bd%20)
where d is the 'correctional number' as I like to call it - i.e. the number that converts the expanded bracket into the +c, since the expanded bracket will give us
![a x^{2} +b](https://tex.z-dn.net/?f=a%20x%5E%7B2%7D%20%2Bb)
.
In this case, 2/2=1 so we have the first part:
![(w+1)^2](https://tex.z-dn.net/?f=%28w%2B1%29%5E2)
.
Expanding this gives us
![w^2+2w+1](https://tex.z-dn.net/?f=w%5E2%2B2w%2B1)
. We need c to be 9, so we can just add 8.
Putting this together:
![w^2+2w+9=(w+1)^2+8](https://tex.z-dn.net/?f=w%5E2%2B2w%2B9%3D%28w%2B1%29%5E2%2B8)
Now we can solve it more easily.
Rearranging:
Answer:
All rational numbers less than 7
Step-by-step explanation:
Answer:
honestly wish math would just jump off the planet with that fancy ole brown necklace we call a rope.
Answer:
1/y+4
Step-by-step explanation:
1-5+1/y+8
1/y+(1-5+8)
1/y+4
Answer:
12.7 years to the nearest tenth.
Step-by-step explanation:
The total of the ages for the 25 students = 10*25 = 250.
For the 30 students it is 15*30 = 450.
The average for the 2 classes = (250 + 450) / (25 + 30)
= 700 / 55
= 12.7 years to the nearest tenth.