Please help, Ive been stuck on this the whole day and I’m so tired rn but I need to submit this before the end of today

Trava [24]

To solve:

Every two days, the cow increases by 6lbs.
To find the unit rate, divide 6 by 2 to find the increase in weight per day.

Unit rate increase: 3lbs

To find the weight on the third day, add 3lbs onto day 2's weight.

85+3=88

Answer: A) The calf's weight is 88lbs on the third day.

7 0

3 years ago

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Before we can make the mashed potatoes, we need to boil some water. The water starts out at room temperature, 70° F, and increas

Karolina [17]

Answer:

Part a) $y=50t+70$

Part b) $t=2.84\ min$

Step-by-step explanation:

Part a) Create a linear equation

Let

t ----> the time in minutes

y ---> the temperature in °F

we know that

The linear equation in slope intercept form is equal to

$y=mt+b$

where

m is the slope or unit rate of the linear equation

b is the y-intercept or initial value of the linear equation

In this problem we have

The slope m is equal to

$m=50\° F\ per\ minute$

The y-intercept is

$b=70\° F$

substitute

$y=50t+70$

Part b) How many minutes until the water boils at 212° F?

For y=212° F

substitute in the linear equation and solve for t

$212=50t+70$

$50t=212-70$

$50t=142$

$t=2.84\ min$

6 0

3 years ago

A simple random sample of 60 households in city 1 is taken. In the sample, there are 45 households that decorate their houses wi

murzikaleks [220]

Answer:

The calculated value of z = - 0.197 falls in the critical region therefore we reject the null hypothesis and conclude that at the 5% significance level there is significant difference in population proportions of households that decorate their houses with lights for the holidays

Step-by-step explanation:

We formulate the null and alternative hypotheses as

H0: p1= p2 there is no difference in population proportions of households that decorate their houses with lights for the holidays

against Ha : p1≠ p2 (claim) ( two sided)

The significance level is set at ∝= 0.05

The critical value for two tailed test at alpha=0.05 is ± 1.96

or Z∝= 0.05/2= ± 1.96

The test statistic is

Z = p1-p2/√pq(1/n1 +1/n2)

p1= proportions of households decorating in city 1 = 45/60=0.75

p2= proportions of households decorating in city 2 = 40/50= 0.8

p = the common proportion on the assumption that the two proportion are same.

p = $\frac{n_1p_1 +n_2p_2}{n_1+n_2}$

Calculating

p =60 (0.75) + 50 (0.8) / 110

p= 45+ 40/110= 85/110 = 0.772

so q = 1-p= 1- 0.772= 0.227

Putting the values in the test statistic and calculating

z= 0.75- 0.8/ √0.772*0.227( 1/60 + 1/50)

z= -0.05/√ 0.175244 ( 110/300)

z= -0.05/0.25348

z= -0.197

The calculated value of z = - 0.197 falls in the critical region therefore we reject the null hypothesis and conclude that at the 5% significance level there is significant difference in population proportions of households that decorate their houses with lights for the holidays

4 0

3 years ago

Three transformations will be performed on triangle ABC. Which set of transformations will always produce a congruent triangle?

Airida [17]

Answer: C (Rotation, Translation and Reflection )

Step-by-step explanation:

A congruence transformation is the type that won't change the shape of the triangle.

They are the reflections(flips), rotations(turns) and translations(slides).

3 0

3 years ago

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The product in lowest terms is ?? please help I've been stuck on this for hours

victus00 [196]

U multiply 1 x 17 x 2
The answer is 34 cm3(cubed)
The 3 behind cm is an exponent

5 0

3 years ago