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3 years ago

Please help me!!!!!!!!!!!!!!

Mathematics

2 answers:

Trava [24]3 years ago

7 0

To solve:

Every two days, the cow increases by 6lbs.
To find the unit rate, divide 6 by 2 to find the increase in weight per day.

Unit rate increase: 3lbs

To find the weight on the third day, add 3lbs onto day 2's weight.

85+3=88

Answer: A) The calf's weight is 88lbs on the third day.

GREYUIT [131]3 years ago

7 0

88 since ever 2 days he gains 6lbs. It seem to gain 3lbs a day

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mrs.beluga is driving on a snow covered road with a drag factor of 0.2. she brakes suddenly for a deer. The tires leave a yaw ma

Aneli [31]

First, we are going to find the radius of the yaw mark. To do that we are going to use the formula: $r= \frac{c^2}{8m} + \frac{m}{2}$
where
$c$ is the length of the chord
$m$ is the middle ordinate
We know from our problem that the tires leave a yaw mark with a 52 foot chord and a middle ornate of 6 feet, so $c=52$ and $m=6$ . Lets replace those values in our formula:
$r= \frac{52^2}{8(6)} + \frac{6}{2}$
$r= \frac{2704}{48} +3$
$r= \frac{169}{3} +3$
$r= \frac{178}{3}$

Next, to find the minimum speed, we are going to use the formula: $s= \sqrt{15fr}$
where
$f$ is drag factor
 $r$ is the radius
We know form our problem that the drag factor is 0.2, so $f=0.2$ . We also know from our previous calculation that the radius is $\frac{178}{3}$ , so $r= \frac{178}{3}$ . Lets replace those values in our formula:
$s= \sqrt{(15)(0.2)( \frac{178}{3}) }$
$s= \sqrt{178}$
$s=13.34$ mph

We can conclude that Mrs. Beluga's minimum speed before she applied the brakes was 13.34 miles per hour.

8 0

3 years ago

A biologist uses a box-shaped fish trap that measures 1/4meter by 2/3meter by 3/5meter. What is the volume of the trap in the cu

Travka [436]

To find the volume of a box-shaped fish trap, we have to multiply the three dimensions of it:

(1/4 m)* (2/3 m)* (3/5 m)

= (1*2*3)/ (4*3*5) m^(3)

= 6/ 60 m^(3)

= 1/10 m^(3)

= 0.1 m^(3)

The volume of the box-shaped fish trap is 0.1 m^(3).

Hope this is helpful~

7 0

3 years ago

Solve the equation X³+2X²-5X -6

Natali [406]

Answer: x = {-1, -3, 2}

Step-by-step explanation:

x³ + 2x² - 5x - 6 = 0

Use the rational root theorem to find the possible roots: ±1, ±2, ±3, ±6

Use Long division, Synthetic division, or plug them into the equation to see which root(s) work (result in a remainder of zero).

I will use Synthetic division. Let's try x = 1

1 | 1 2 -5 -6

| ↓ 1 3 -2

1 3 -2 -8 ← remainder ≠ 0 so x = 1 is NOT a root

Let's try x = -1

- 1 | 1 2 -5 -6

| ↓ -1 -1 6

1 1 -6 0 ← remainder = 0 so x = -1 is a root!

The coefficients of the reduced polynomial are: 1, 1, -6 --> x² + x - 6

Factor: x² + x - 6

(x + 3)(x - 2)

Set those factors equal to zero to solve for x:

x + 3 = 0 --> x = -3

x - 2 = 0 --> x = 2

Using Synthetic Division and Factoring the reduced polynomial, we found

x = -1, -3, and 2

6 0

3 years ago

Help me ... question is in the picture and the answer choices are

Strike441 [17]

$\left(\dfrac{2m+2p}{2},\dfrac{2n+2r}{2}\right)=\left(m+p,n+r\right)$

6 0

3 years ago

Point S is on line segment R T ‾ RT . Given R S = 4 x − 10 , RS=4x−10, S T = 2 x − 10 , ST=2x−10, and R T = 4 x − 4 , RT=4x−4, d

mylen [45]

Question not well presented

Point S is on line segment RT . Given RS = 4x − 10, ST=2x−10, and RT=4x−4, determine the numerical length of RS

Answer:

The numerical length of RS is 22

Step-by-step explanation:

Given that

RS = 4x − 10

ST=2x−10

RT=4x−4

From the question above:

Point S lies on |RT|

So, RT = RS + ST

Substitute values for each in the above equation to solve for x

4x - 4 = 4x - 10 + 2x - 10 --- collect like terms

4x - 4 = 4x + 2x - 10 - 10

4x - 4 = 6x - 20--- collect like terms

6x - 4x = 20 - 4

2x = 16 --- divide through by 2

2x/2 = 16/2

x = 8

Since, RS = 4x − 10

RS = 4*8 - 10

RS = 32 - 10

RS = 22

Hence, the numerical length of RS is calculated as 22

8 0

3 years ago