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aliya0001 [1]
3 years ago
15

Please help me!!!!!!!!!!!!!!

Mathematics
2 answers:
Trava [24]3 years ago
7 0
To solve:

Every two days, the cow increases by 6lbs.
To find the unit rate, divide 6 by 2 to find the increase in weight per day.

Unit rate increase: 3lbs

To find the weight on the third day, add 3lbs onto day 2's weight.

85+3=88


Answer: A) The calf's weight is 88lbs on the third day. 
GREYUIT [131]3 years ago
7 0
88 since ever 2 days he gains 6lbs. It seem to gain 3lbs a day
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Answer:  see below

<u>Step-by-step explanation:</u>

C(x) = 39 when 0 < x ≤ 1.0

C(x) = 63 when 1.0 < x ≤ 2.0

C(x) = 87 when 2.0 < x ≤ 3.0

C(x) = 111 when 3.0 < x ≤ 4.0

C(x) = 135 when 4.0 < x ≤ 5.0

C(x) = 159 when 5.0 < x ≤ 6.0

Based on the information I provided above, the answers are:

a) x= 0.6, C(x) = 1.0

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   x = 1.1,  C(x) = 63

   x = 2.5, C(x) = 87

   x = 3.0, C(x) = 87

   x = 4.8, C(x) = 135

   x = 5.0, C(x) = 135

   x = 5.3, C(x) = 159

b) If C(x) = 87, then 2.0 < x ≤ 3.0

c) Domain (all possible x-values): 0 < x ≤ 6.0

d) Range (all possible y-values): {39, 63, 87, 111, 135, 159}

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