6 dozen were purchased
divide the charge by the cost of one dozen
number purchased = 
= 6
2x + y = 71
y = x + 5
2x + (x + 5) = 71
3x + 5 = 71
3x = 71 - 5
3x = 66
x = 66/3
x = 22 .... small van
y = x + 5
y = 22 + 5
y = 27 <=== larger van
For the first one, its 86 square in, and the second one is 45 square cm.
For this case, we must build a quotient that, when multiplied by the divisor, eliminates the terms of the dividend until it reaches the remainder. In this case we have to:
Remainder: 20
Quotient: 3x-9
It must be fulfilled that:
Dividend = Quotient * Divider + Remainder
Answer:
See attached image
In this question, you're solving for y:
Solve for y:
-3(4y - 7) - y = -2(y - 2)
<em>use the distributive property:</em>
-12y + 21 - y = -2y + 4
<em>combine like terms:</em>
-13y + 21 = -2y + 4
<em>add 2 to both sides</em>
-11y + 21 = 4
<em>subtract 21 from both sides</em>
-11y = -17
<em>divide both sides by -11</em>
y = 17/11
You would check your answer by plugging in 17/11 to the y variables.
