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3 years ago

Type the missing number that makes these fractions equal: 4 10 = 2.

1 answer:

6 0

Answer: I assume this ques was formatted like this originally. 4/10 = 2. If so the answer is 5 making the second fraction 2/5. Let me know if this is not the case. Hope this helps!

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Santa and his elves had a workshop that allowed them to produce 22{,}912{,}546{,}99222,912,546,99222, comma, 912, comma, 546, co

zvonat [6]

Answer: 180 times

Step-by-step explanation:

Given the following :

Production capacity of old workshop :22,912,546,992 toys per year

Production capacity of new workshop:

4,134,232,638,937 toys

Approximately how many times as many toys can the new workshop produce each year compared to the old workshop?

Production capacity of new workshop / production capacity of old workshop

= 4,134,232,638,937 / 22,912,546,992

= 180.435

= 180 ( nearest whole number)

3 0

4 years ago

Question Number 2!! Thank youu

rewona [7]

Answer:

56°

Step-by-step explanation:

Since triangle ABD and triangle CBD are congruent (SAS), so you can divide m∠ABC by 2 to get the m∠ABD and m∠CBD, or 56°.

3 0

2 years ago

Okay, help me out here!!

luda_lava [24]

Answer:

65.8

Step-by-step explanation:

(2.6*4.7)/2=6.11

11*4.7=51.7

(4.7(17-(2.6+11)))/2=7.99

6.11+51.7+7.99=65.8

3 0

3 years ago

Angle $eab$ is a right angle, and $be = 9$ units. what is the number of square units in the sum of the areas of the two squares

Alla [95]

Let the measure of side AB be x, then, the measue of side AE is given by

$AE=\sqrt{9^2-x^2}$ .

Now, ABCD is a square of size x, thus the area of square ABCD is given by

$Area=x^2$

Also, AEFG is a square of size $\sqrt{9^2-x^2}$ , thus, the area of square AEFG is given by

$Area=\left(\sqrt{9^2-x^2}\right)^2=9^2-x^2=81-x^2$

<span>The sum of the areas of the two squares ABCD and AEFG is given by

$x^2+81-x^2=81$

Therefore, </span>the number of square units in the sum of the areas of the two squares <span>ABCD and AEFG is 81 square units.</span>

8 0

3 years ago

Two sets of quadratic expressions are shown below in various forms: Line 1: x2 + 3x + 2 (x + 1)(x + 2) (x + 1.5)2 − 0.25 Line 2:

Serga [27]

Its line 1

if we expand the second and third expressions they come back to the first.

The last one is called the vertex form of a parabola

5 0

3 years ago