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andriy [413]
3 years ago
12

Write an iterated integral for ModifyingBelow Integral from nothing to nothing Integral from nothing to nothing Integral from no

thing to nothing With Upper D f (x comma y comma z )dV where D is a sphere of radius 9 centered at​ (0,0,0). Use the order dy dz dx .
Mathematics
1 answer:
coldgirl [10]3 years ago
8 0

With the given order of integration, the interval over D is

\displaystyle \iiint_D f(x,y,z) \, dV = \int_{-3}^{3} \int_{-\sqrt{9-x^2}}^{\sqrt{9-x^2}} \int_{-\sqrt{9-x^2-z^2}}^{\sqrt{9-x^2-z^2}} f(x,y,z) \, dy \, dz \, dx

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Maria's family drove 140 mi to her grandparents' house and averaged 56 ​ mi/h ​ on the way there. On the return trip, they avera
GaryK [48]

Answer: 5.3 Hours


Step-by-step explanation: 140 mi there at 56 mi per hour would be 2.5 hours. Then back 140 mi at 50 mi/h would be 2.8. 2.5 plus a 2.8 is 5.3 hours


4 0
3 years ago
Which linear function is represented by the graph?
professor190 [17]

9514 1404 393

Answer:

 f(x) = -1/2x +1

Step-by-step explanation:

The line crosses the y-axis at y=1, so the y-intercept is b=1.

The line drops 1 unit for a run of 2 to the right, so the slope is ...

  m = rise/run = -1/2

The slope-intercept form of the equation of the line is ...

  y = mx + b

  y = -1/2x + 1

In functional form, the equation is ...

  f(x) = -1/2x +1

8 0
3 years ago
If (6 to the second power )x = 1 what is the value of x? Explain your answer.
Kaylis [27]

Answer:

x=1/36

Step-by-step explanation:

(6^{2} )x=1\\\\36x=1\\\\\frac{36x}{36}=\frac{1}{36}\\\\x=\frac{1}{36}

4 0
3 years ago
Given the graph of f'(x) shown below, find the intervals on which the function f(x) is increasing.
AURORKA [14]

Answer:

intervals (-3,-1) and (0,+infinity)

Step-by-step explanation:

if f'(x)>0 then f is increasing

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%284%20%2B%206i%29%20%7B%7D%5E%7B2%7D%20" id="TexFormula1" title="(4 + 6i) {}^{2} " alt="(4 +
34kurt

Answer:

36i^{2}+48i+16

Step-by-step explanation:

(4+6i)^{2} is essentially (4+6i)(4+6i) (you are squaring (4+6i), so multiplying it by itself), so to simplify, you would need to distribute.

A good way to go about this is using the F.O.I.L. method, multiplying the First numbers in the parentheses, then the Outers, then Inners, and finally, Lasts.

(4+6i)(4+6i) >> (4+6i)(4+6i) >> (4+6i)(4+6i) >> (4+6i)(4+6i)

((4*4)+(4*6i)+(6i*4)(6i*6i))

After doing so, you would end up with 16+24i+24i+36i^{2}, and after combining like terms, 16+48i+36i^{2}.

To write the expression in standard form, though, just order the terms from highest to lowest power!

5 0
3 years ago
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