A. ratio of areas = 2^2 /5^2 = 4/25
B 14^2 : 1 = 196:1
C. ratio of perimeters would be sqrt81 = 9 times
Answer:
3 =n
Step-by-step explanation:
-3 +3(n+8)= 2(1 + 6n) - 8
Distribute
-3 +3n +24 = 2 +12n -8
Combine like terms
21+3n = 12n -6
Subtract 3n from each side
21+3n-3n = 12n-3n -6
21 = 9n -6
Add 6 to each side
21+6 = 9n-6+6
27 = 9n
Divide each side by 9
27/9 = 9n/9
27/9 =n
Divide the top and bottom by 3
3 =n
Answer:
1335cm³
Step-by-step explanation:
The question above says that,Krispy kritters cereal used to come in a box with a volume of 2,850 cm3. However, the krispy kritters co. Designed a new larger box 22.5 cm wide, 6.2 cm deep, and 30 cm high and we are now asked to find "How many more cubic centimeters will the new box hold than the old box?
Now we are all aware that the volume of a cube or cuboid(since its a box ) is length multipled by width multiplied by the height.
And we were given the new dimensions which are;
12.5cm wide
6.2cm deep and
30cm high
Apply this given figures in the formula above and we have:
V = 12.5 × 6.2 × 30
= 4185cm³( this is the volume of the box)
Therefore,the difference in volume between the new box and the old box is
4185 - 2850 = 1335cm³
This problem can be solved by the chicken rabbits method or you can just do simple algebra.
I.) Chicken and rabbits method
First assume all 110 coins are dimes and none are quarters.
We will have a total value of 11 dollars
Now for each dime we switch out for a quarter, we adds 15 cents to the total value.
18.50-11=7.50 dollars
There are 750/15=50 group of 15 cents in the 7 dollars and 50 cents.
This also meant that we need to switch out 50 dimes for 50 quarters.
So we have 50 quarters.
That first method is very good and very quick once you get the hang of it, now I'm going to show you the algebraic way to solve this.
Let's say there are x dimes and y quarters.
Set up equation
x+y=110
10x+25y=1850
Now solve multiply first equation by 10
10x+10y=1100
subtract
15y=750
y=50
Now we set the numbers of quarters to y so the answer is 50 quarters.
I personally recommend using algebra whenever you can because the practice is very important and you will eventually get really fast at setting up and solving equations. The first method is faster in this case but the second is more generalize, hope it helps.
The answer is B, I hope this helps! (don't forget to give brainliest)
