36 two credit courses and 11 three credit courses has been taken.
<u>SOLUTION:
</u>
Given, each course in college X is worth either two or three credits. The members of the men’s swim team are taking a total of 47 courses that are worth a total of 105 credits
.
We have to number of two credit courses and three credit courses are being taken
.
Now, let the number of 2 credits courses be n, then number of 3 credits courses will be .
And, according to the given information, Total credits = 105
So, two credits courses count is 36, the three credit courses count is
Using z-scores for 130 and 140 hours, and a standard normal distribution table, the cumulative probabilities for 130 and 140 hours are 0.254 and 0.673 respectively.
The required probability is 0.673 - 0.254 = 0.42 to 2 d.p.
What do ya got? I need the equation and a little explanation of what needs to be done.
<span>9 (p − 4) = 18
9p - 36 = 18
9p = 18 + 36
9p = 54
p = 54/9
p = 6</span>