Answer:
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Answer:
i am doing online school
Step-by-step explanation:
I think the answer is A, it increases.
Why?
Just put x = 3 into f(x)=6x and you get f(x) = 18
Put x = 4 into f(x) and you get f(x) = 24
Subtract those two. 24 - 18 = 6
Also, f(x) = 6x it will always be 6 away from the next x you put into the equasion.
Or better said, it will be 6 more from 6x, because you are changing the x to X+1, hence,
6(x+1) = 6x + 6.
+6, it increases.
Answer and Step-by-step explanation:
(a) Given that x and y is even, we want to prove that xy is also even.
For x and y to be even, x and y have to be a multiple of 2. Let x = 2k and y = 2p where k and p are real numbers. xy = 2k x 2p = 4kp = 2(2kp). The product is a multiple of 2, this means the number is also even. Hence xy is even when x and y are even.
(b) in reality, if an odd number multiplies and odd number, the result is also an odd number. Therefore, the question is wrong. I assume they wanted to ask for the proof that the product is also odd. If that's the case, then this is the proof:
Given that x and y are odd, we want to prove that xy is odd. For x and y to be odd, they have to be multiples of 2 with 1 added to it. Therefore, suppose x = 2k + 1 and y = 2p + 1 then xy = (2k + 1)(2p + 1) = 4kp + 2k + 2p + 1 = 2(kp + k + p) + 1. Let kp + k + p = q, then we have 2q + 1 which is also odd.
(c) Given that x is odd we want to prove that 3x is also odd. Firstly, we've proven above that xy is odd if x and y are odd. 3 is an odd number and we are told that x is odd. Therefore it follows from the second proof that 3x is also odd.
Answer: 314.16 or 100 pie
Step-by-step explanation:
2(50)pie