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3 years ago

Imma need sum help please

Mathematics

1 answer:

MrRa [10]3 years ago

8 0

Answer:

Step 5

Step-by-step explanation:

The mistake is in step 5.

The previous step was

$step \: 4 : 2 + 10 \div 2$

The order operations, PEDMAS, must be applied:

We have Addition and Division here,

Using PEDMAS, we must divide first to get:

$step \: 5 : 2 + 5$

We can now add to get:

$step \: 6: 7$

Therefore the mistake occurred at step 5

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Answer:

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Step-by-step explanation:

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2 years ago

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tigry1 [53]

Answer:

1. total volume of box=2.5(V)D

2. 7 Drawers

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6 0

1 year ago

Bojangles has a rectangle-shaped roof with a width of 6x^2 feet and a length 12x^3. What is the area of the roof?

emmainna [20.7K]

area of rectangle = length x width

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2 years ago

PLs answer fast i need this questions answer

Mashutka [201]

Answer:

$x=6$

Step-by-step explanation:

Given equation:

$x-\left(2x-\dfrac{3x-4}{7}\right)=\dfrac{4x-27}{3}-3$

Expand the left side:

$\implies x-2x+\dfrac{3x-4}{7}=\dfrac{4x-27}{3}-3$

Let all terms on the left side have the same denominator of 7:

$\implies \dfrac{7x}{7}-\dfrac{14x}{7}+\dfrac{3x-4}{7}=\dfrac{4x-27}{3}-3$

Join the terms on the left side:

$\implies \dfrac{7x-14x+3x-4}{7}=\dfrac{4x-27}{3}-3$

$\implies \dfrac{-4x-4}{7}=\dfrac{4x-27}{3}-3$

Let all the terms on the right side have the same denominator of 3:

$\implies \dfrac{-4x-4}{7}=\dfrac{4x-27}{3}-\dfrac{9}{3}$

Join the terms on the right side:

$\implies \dfrac{-4x-4}{7}=\dfrac{4x-27-9}{3}$

$\implies \dfrac{-4x-4}{7}=\dfrac{4x-36}{3}$

Cross multiply:

$\implies 3(-4x-4)=7(4x-36)$

Expand:

$\implies -12x-12=28x-252$

Add 12x to both sides:

$\implies -12=40x-252$

Add 252 to both sides:

$\implies 240=40x$

Divide both sides by 40:

$\implies 6=x$

$\implies x=6$

6 0

1 year ago