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3 years ago

Equation for the line that passes through (4,7) and is perpendicular to the line Y= 2/3x-1

Mathematics

2 answers:

alexdok [17]3 years ago

8 0

Answer:

y = -3/2x + 13

Step-by-step explanation:

In order for a line to be perpendicular, it must have an opposite reciprocal slope to the given line. In this instance, the opposite reciprocal of 2/3 would be -3/2. Insert the information given into the point-slope formula.

$y-7=-\frac{3}{2}(x-4)\\\\y-7=-\frac{3}{2}x+6\\\\y=-\frac{3}{2}x+13$

hichkok12 [17]3 years ago

3 0

Answer: y=-3/2x+13

Step-by-step explanation:

(4,7) m=2/3

x,y m⊥=-3/2

7=-3/2(4)+b

7=-6+b

13=b

y=-3/2x+13

feel free to let me know if its wrong

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The width of a rectangle is the length minus 3 units. The area of the rectangle is 54 units. What is the width, in units, of a r

saul85 [17]

Width of the rectangle is 9 units

Step-by-step explanation:

Step 1: Let the width of the rectangle be x. Then the length = x - 3. Find dimensions of the rectangle if its area = 54 sq. units

Area of the rectangle = length × width

54 = x (x - 3)

54 = x² - 3x

x² - 3x - 54 = 0

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x(x + 6) - 9(x + 6) = 0

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3 years ago

4x + 5y = 22 7x - 3y = -32

lana66690 [7]

Answer:

x = -2

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Step-by-step explanation:

i multiplied the 1st equation by 3 and the 2nd by 5 to get the y-terms to zero out

12x + 15y = 66

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47x = -94

x = -94/47

x = -2

substitute -2 for 'x' to solve for 'y':

4(-2) + 5y = 22

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3 0

3 years ago

92 divided by 4 use partial and quotients to divide

kherson [118]

The partial quotient is 23

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3 years ago

Read 2 more answers

The equation of the line that goes through the points ( − 3 , − 9 ) and ( − 6 , − 3 ) can be written in the form y = m x + b

ivolga24 [154]

Answer:

$y=-2x-15$

Step-by-step explanation:

$y=mx+b$ .

m is the slope of the line. To find it we can do $\frac{dy}{dx}$ which is the difference between the y-coordinates divided by the difference between the x-coordinates.

So: $\frac{dy}{dx} =\frac{-9-(-3)}{-3-(-6)} =\frac{-6}{3} =-2$ . Now we have the slope, let's input a set of coordinates into the equation so that we can find the constant $b$ .