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AVprozaik [17]
2 years ago
9

Equation for the line that passes through (4,7) and is perpendicular to the line Y= 2/3x-1

Mathematics
2 answers:
alexdok [17]2 years ago
8 0

Answer:

y = -3/2x + 13

Step-by-step explanation:

    In order for a line to be perpendicular, it must have an opposite reciprocal slope to the given line. In this instance, the opposite reciprocal of 2/3 would be -3/2. Insert the information given into the point-slope formula.

y-7=-\frac{3}{2}(x-4)\\\\y-7=-\frac{3}{2}x+6\\\\y=-\frac{3}{2}x+13

hichkok12 [17]2 years ago
3 0

Answer: y=-3/2x+13

Step-by-step explanation:

(4,7)   m=2/3

x,y     m⊥=-3/2

7=-3/2(4)+b

7=-6+b

13=b

y=-3/2x+13

feel free to let me know if its wrong

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You can find this by factoring. Start by pulling out the greatest common factor, which in this case is -x^2.


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Now we can factor the inside of the parenthesis. You do this by finding factors of the last number that add up to the middle number.


-x^2(x^4 - 3x^2 - 4)

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Now we can use the factors of two perfect squares rule to factor the middle parenthesis.


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We would also want to split the term in the front.


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Now we would set each portion equal to 0 and solve.


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Second root

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Fifth and Sixth roots

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x = +/- \sqrt{-1}

x = +/- i

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3 years ago
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