Glucose is the preferable source of energy for E. coli cells. By adding small amounts of glucose, 0.05% in this case, it would enable cell growth to proceed as usual until it has reached mid log growth phase. At this point, the small amount of glucose added should have been depleted and the E.coli cell will now be dependent on lactose present as its source of nutrients. Lactose will also inactivate lac repressors and given the lack of glucose, CAP binding to high amounts of cAMP will be activated and increase expression of lac operon genes.
It should be noted that this system of expression may not tightly regulate the expression of lac operon before the E.Coli reaches exponential phase. As lactose is still present, lac repressors will be inactivated throughout the entire experiment and hence small amounts of proteins might be produced even when not auto-induced. After auto-induction, CAP-cAMP protein complex will simply upregulate expression of lac operon genes.
Answer:
Muscle Cells and Nerve Cells
Listen the guy who answered the other one is wrong its not blood cells
Answer:
Explanation:
While passing through renal tubules, water and a lot of other substances are reabsorbed making filtrate concentrated. This also gradually results in an increase in the concentration of urea as it is not reabsorbed like water or glucose. Some substances like K+, H+ are also secreted (not urine).
The pair that incorrectly matches polymer-monomer is lipids-monosaccharides (option C).
<h3>What is a monomer?</h3>
A monomer is a small molecule which can be covalently bonded to other monomers to form a polymer.
A polymer, on the other hand, is a large molecule made up of a chain of many monomeric units, formed by chemically bonding together.
The following are the monomer-polymer combination we have in nature;
- Carbohydrates - simple sugar/monosaccharide
- Protein - amino acid
- Lipids - fatty acid
- Nucleic acid - nucleotide
Therefore, the pair that incorrectly matches polymer-monomer is lipids-monosaccharides.
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