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tino4ka555 [31]
3 years ago
6

How do you get lugia in pokemon alpha saphire

Computers and Technology
1 answer:
sleet_krkn [62]3 years ago
4 0

Answer:

You'd have to have encountered Groudon in your story first. You're able to unlock Lugia as early as the battle with the 8th gym leader. First go east of Dufour town, once you landed on the ship go underwater to the control room. Pick up the scanner, and go to Captain Stern in the Stateport city ship dock. Give him the scanner, and he will give you a bell. Go back to Sea Marvel and notice your item start to resonate. There will be a portal underwater in the control room. Go through it and after that you'll see what happens, depending on which bell you have.

Explanation:

Hope this helped!!! Good luck!- Nya~ :3

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If Asa changes the text to bold, he has changed the style. True False
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True because if you were to bold a text, you have presented that the following text is more important or exemplified. 
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3 years ago
Read 2 more answers
int temp; temp = 180; if ( temp > 90 ) { System.out.println( "This porridge is too hot." ); // cool down temp = temp – ( temp
STALIN [3.7K]

Answer:

The combined output will be option D which is

This porridge is too hot.

This porridge is just right!

Explanation:

As the complete question is not the given the complete question is found online and is attached herewith.

Now from the given attached code

As the temperature value is 180 which is more than 90 so the first loop is true and the first print out is

This porridge is too hot.

Now the temperature is cooled down using the formula such that the temperature reduced 100 degrees in the intervals of 20 now the temperature becomes 80. As it is greater than 70, thus the second if loop is not executed.

As the temperature is 80 this the next print out will be as

This porridge is just right!

So the combined output will be option D which is

This porridge is too hot.

This porridge is just right!

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3 years ago
Write a function wordcount() that takes the name of a text file as input and prints the number of occurrences of every word in t
o-na [289]

Answer:

I am writing a Python program. Let me know if you want the program in some other programming language.        

import string  #to use string related functions

def wordcount(filename):  # function that takes a text file name as parameter and returns the number of occurrences of every word in file

   file = open(filename, "r")  # open the file in read mode

   wc = dict()  # creates a dictionary

   for sentence in file:  # loop through each line of the file

       sentence = sentence.strip()  #returns the text, removing empty spaces

       sentence=sentence.lower() #converts each line to lowercase to avoid case sensitivity

       sentence = sentence.translate(sentence.maketrans("", "", string.punctuation))  #removes punctuation from every line of the text file

       words = sentence.split(" ")  # split the lines into a list of words

       for word in words:  #loops through each word of the file

           if len(word)>2:  #checks if the length of the word is greater than 2

               if word in wc:  # if the word is already in dictionary

                   wc[word] = wc[word] + 1  #if the word is already present in dict wc then add 1 to the count of that word

               else:  #if the word is not already present

                   wc[word] = 1  # word is added to the wc dict and assign 1 to the count of that word                

   for w in list(wc.keys()):  #prints the list of words and their number of occurrences

       print(w, wc[w])  #prints word: occurrences in key:value format of dict        

wordcount("file.txt") #calls wordcount method and passes name of the file to that method

Explanation:

The program has a function wordcount that takes the name of a text file (filename) as parameter.

open() method is used to open the file in read mode. "r" represents the mode and it means read mode. Then a dictionary is created and named as wc. The first for loop, iterates through each line (sentence) of the text file. strip() method is used to remove extra empty spaces or new line character from each sentence of the file, then each sentence is converted to lower case using lower() method to avoid case sensitivity. Now the words "hello" and "Hello" are treated as the same word.

sentence = sentence.translate(sentence.maketrans("", "", string.punctuation))  statement uses two methods i.e. maketrans() and translate(). maketrans() specifies the punctuation characters that are to be deleted from the sentences and returns a translation table. translate() method uses the table that maketrans() returns in order to replace a character to its mapped character and returns the lines of text file after performing these translations.

Next the split() method is used to break these sentences into a list of words. Second for loop iterates through each word of the text file. As its given to ignore words of length 2 or less, so an IF statement is used to check if the length of word is greater than 2. If this statement evaluates to true then next statement: if word in wc:   is executed which checks if the word is already present in dictionary. If this statement evaluates to true then 1 is added to the count of that word. If the word is not already present  then the word is added to the wc dictionary and 1 s assigned to the count of that word.

Next the words along with their occurrences is printed. The program and its output are attached as screenshot. Since the frankenstein.txt' is not provided so I am using my own text file.

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Answer:

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Packaged software is a compilation of programs which are grouped together in order to provide publicly with different tools in the same group.

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