All categories

2 years ago

Write an equation in slope-intercept form of the line shown (1,-9) , (-3,-9)

Mathematics

1 answer:

vlabodo [156]2 years ago

5 0

Answer:

y = -9

Step-by-step explanation:

y2 - y1 / x2 - x1

-9 - (-9) / -3 - 1

0 / -4

y = 0 + b

-9 = b

You might be interested in

Please I need help with this Question

frutty [35]

Answer:

The data set with the greater range is the Girls

The greater median is the Girls at 110

Step-by-step explanation:

The range is the difference between the largest and smallest values.

As the largest value for the boys is 120 and the smallest is 60, the range would be 60

As the largest value for the girls is 150 and the smallest is 70, the range would be 80.

This means that the Girls have the greater range

The median is the number in the middle when the data is in ascending order.

As we have an even number, we will have to find the middle value between 5 and 6. To do this, we can add them together and divide them by 2.

The 5th boy in ascending order is 90 and the 6th boy is 90.

$(90+90)/2=90$

The 5th 5irl is 100 and the 6th girl is 120

$(100+120)/2=110$

This means that the median is greater for the Girls.

4 0

3 years ago

URGENT HELP ME PLEASE

Trava [24]

Answer:

(a) $\log_3(\dfrac{81}{3})=3$

(b) $\log_5(\dfrac{625}{25})=2$

(d) $\log_4(\dfrac{64}{16})=1$

(e) $\log_6(36^4)=8$

(f) $\log(100^3)=6$

Step-by-step explanation:

Let as consider the given equations are $\log_3(\dfrac{81}{3})=?,\log_5(\dfrac{625}{25})=?,\log_2(\dfrac{64}{8})=?,\log_4(\dfrac{64}{16})=?,\log_6(36^4)=?,\log(100^3)=?$ .

(a)

$\log_3(\dfrac{81}{3})=\log_3(27)$

$\log_3(\dfrac{81}{3})=\log_3(3^3)$

$\log_3(\dfrac{81}{3})=3$ $[\because \log_aa^x=x]$

(b)

$\log_5(\dfrac{625}{25})=\log_5(25)$

$\log_5(\dfrac{625}{25})=\log_5(5^2)$

$\log_5(\dfrac{625}{25})=2$ $[\because \log_aa^x=x]$

(c)

$\log_2(\dfrac{64}{8})=\log_2(8)$

$\log_2(\dfrac{64}{8})=\log_2(2^3)$

$\log_2(\dfrac{64}{8})=3$ $[\because \log_aa^x=x]$

(d)

$\log_4(\dfrac{64}{16})=\log_4(4)$

$\log_4(\dfrac{64}{16})=1$ $[\because \log_aa^x=x]$

(e)

$\log_6(36^4)=\log_6((6^2)^4)$

$\log_6(36^4)=\log_6(6^8)$

$\log_6(36^4)=8$ $[\because \log_aa^x=x]$

(f)

$\log(100^3)=\log((10^2)^3)$

$\log(100^3)=\log(10^6)$

$\log(100^3)=6$ $[\because \log10^x=x]$

5 0

3 years ago

Shadow Software company earned a total of 800,009 selling programs during the year 2012. 125,300 of taht amount was used to pay

Softa [21]

Subtract 125,300 from 800,009. From there you find that they made 674,709 in profit. Answer is 674,709

6 0

3 years ago

I NEED HELP WITH THIS ASAP

madreJ [45]

Answer:

I think its AED19

Step-by-step explanation:

please give brainliest if correct

3 0

3 years ago

Can someone please explain how they got this answer because the entire lesson they haven’t shown me how to graph these

I am Lyosha [343]

Answer:

Please check explanations

Step-by-step explanation:

Here, we have three types of equations and three plotted graphs

we have a quadratic equation

an exponential equation

and a linear equation

For a quadratic equation, we usually have a parabola

The first equation is quadratic and as such the first graph that is parabolic belongs to it

For an exponential equation, we usually have a graph that rises or falls before becoming flattened

The second equation represents an exponential equation so the second graph is for it

Lastly, we have a linear equation

A linear equation usually has a straight line graph

Thus, as we can see, the third graph represents the linear equation

5 0

3 years ago