Lines AB, CD, and EF intersect at point G. How many PAIRS of vertical angles are there in this diagram

Linda watched a video. The introduction is 2 minutes, and the video is 7 minutes. What percentage of the video is the introducti

kolezko [41]

Answer:

22.222222%

Step-by-step explanation:

all together the entire video is 9 min and 2 of those are the intro so 2/9 and that as a percent is the answer

4 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%5Cbegin%7Bequation%7D%5Ctext%20%7B%20Question%3A%20Find%20the%20value%20of%20%7D%20%5Cfrac%7B

ankoles [38]

$\bold{Heya!}$

Your answer to this is:

$\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0}$

<h2>→ <u>EXPLANATION :-</u></h2>

<u />

<u /> $\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0} \: (1)$

$\sf{Apply \: rule:} \: (a) = a$

$\sf{(1) = 1$

$\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0} \: ^. \: 1$

$\sf{\frac{1}{1 \: + \:1} = \frac{1}{2}$

$\sf{\frac{2^1^0^0}{1 \: + \: x^2^0^0} ^.^ \: 1 \: = \: \frac{2^1^0^0}{1 \: + \: x^2^0^0}$

$\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0}$

Hopefully This Helps ! ~

#LearnWithBrainly

$\underline{Answer :}$

<em>Jaceysan ~</em>

7 0

2 years ago

For the following relation, find the: a) Reflexive closure b) Symmetric closure c) Transitive closure 2 You may include explanat

Luba_88 [7]

Answer:

Following are the complete solution in the attached file.

Step-by-step explanation:

5 0

3 years ago

The perimeter of a rectangle

mina [271]

XZ=XY+YZ

JL=JK+KL

use the trigonometric values table or unit circle to calculate the expression

6 0

2 years ago

The graph of g(x) is a transformation of the graph of f(x)=3x. Enter the equation for g(x) in the box. G(x) =.

dalvyx [7]

Function transformation involves changing the form of a function

The function g(x) is $\mathbf{g(x) = 8(2)^x}$

The function is given as:

$\mathbf{f(x) = 3^x}$

g(x) is an exponential function that passes through points (-2,2) and (-1,4).

An exponential function is represented as:

$\mathbf{y = ab^x}$

At point (-2,2), we have:

$\mathbf{2 = ab^{-2}}$

At point (-1,4), we have:

$\mathbf{4 = ab^{-1}}$

Divide both equations

$\mathbf{\frac 42=\frac{ab^{-1}}{ab^{-2}}}$

Simplify

$\mathbf{2=\frac{b^{-1}}{b^{-2}}}$

Apply law of indices

$\mathbf{2=b^{-1+2}}$

$\mathbf{2=b}$

Rewrite as:

$\mathbf{b =2}$

Substitute 2 for b in $\mathbf{2 = ab^{-2}}$

$\mathbf{2 =a(2^{-2})}$

This gives

$\mathbf{2 =a(\frac 14)}$

Multiply both sides by 4

$\mathbf{a = 8}$

Substitute 8 for (a) and 2 for (b) in $\mathbf{y = ab^x}$

$\mathbf{y = 8(2)^x}$

Express as a function

$\mathbf{g(x) = 8(2)^x}$

Hence, the function g(x) is $\mathbf{g(x) = 8(2)^x}$

Read more about exponential functions at:

brainly.com/question/11487261

8 0

2 years ago