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Katarina [22]
3 years ago
10

Over a 24-hour period, the tide in a harbor can be modeled by one period of a sinusoidal function. The tide measures 4.35 ft at

midnight, rises to a high of 8.3 ft, falls to a low of 0.4 ft, and then rises to 4.35 ft by the next midnight.
What is the equation for the sine function f(x), where x represents time in hours since the beginning of the 24-hour period, that models the situation?

f(x)=
Mathematics
1 answer:
netineya [11]3 years ago
8 0

Answer:

  f(x) = 4.35 +3.95·sin(πx/12)

Step-by-step explanation:

For problems of this sort, a sine function is used that is of the form ...

  f(x) = A + Bsin(2πx/P)

where A is the average or middle value of the oscillation, B is the one-sided amplitude, P is the period in the same units as x.

It is rare that a tide function has a period (P) of 24 hours, but we'll use that value since the problem statement requires it. The value of A is the middle value of the oscillation, 4.35 ft in this problem. The value of B is the amplitude, given as 8.3 ft -4.35 ft = 3.95 ft. Putting these values into the form gives ...

  f(x) = 4.35 + 3.95·sin(2πx/24)

The argument of the sine function can be simplified to πx/12, as in the Answer, above.

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Answer:15h

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4 0
2 years ago
What type of sequence is this and how do you use the recursive and explicit rule?
Oksana_A [137]
Arithmetic

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7 0
3 years ago
Please help, me find the area of Letter E.​
Radda [10]

Answer:

7.005 m^2.

Step-by-step explanation:

We can split this into one vertical rectangle   3.45 * 0.9 m^2

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7 0
3 years ago
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Setler79 [48]

The values of the trigonometry ratios are:

  • cos α = - 5/13 and cot α = 5/12
  • cot α = -5/12 and sec α = 13/5

<h3>How to solve the trigonometry ratios?</h3>

<u>1: sin α = -12/13 and tan α > 0, find cos α and cot α</u>

Because tan α > 0, then it means that cos α and sin α are negative

So, we have:

sin²α + cos²α = 1

Substitute sin α = -12/13

(-12/13)² + cos²α = 1

This gives

cos²α = 1 - (-12/13)²

Evaluate the squares

cos²α = 1 - 144/169

Evaluate the difference

cos²α = 25/169

Take the square root of both sides

cos α = - 5/13

The cotangent ratio is represented as:

cot α = cos α/sin α

This gives

cot α = (-5/13)/(-12/13)

Evaluate

cot α = 5/12

Hence, cos α = - 5/13 and cot α = 5/12

<u>2: tan α = -12/5 for α in quadrant IV, find sec α and cot α</u>

Because α is in quadrant IV, then it means that sec α is positive

cot α = 1/tan α

This gives

cot α = 1/(-12/5)

Evaluate

cot α = -5/12

Also, we have:

sec²α = 1 + tan²α

Substitute tan α = -12/5

sec²α = 1 + (-12/5)²

Evaluate the squares

sec²α = 1 + 144/25

Evaluate the sum

sec²α = 169/25

Take the square root of both sides

sec α = 13/5

Hence, cot α = -5/12 and sec α = 13/5

Read more about trigonometry ratios at:

brainly.com/question/11967894

#SPJ1

5 0
2 years ago
Will give brainliest
klemol [59]

Your question is calling the figure ABCD, but the image is showing PQRS


Using the letters that you wrote:

Because the figure was only rotated and not scaled , the sides with the same letters would still be the same

So AB would be the same as A'B' ( Length of AB = Length of A′B)

and

BC = B'C'

CD = C'D'

AD = A'D'


Or by the picture:

PQ = P'Q'

QR = Q'R'

RS = R'S'

PS = P'S'





7 0
3 years ago
Read 2 more answers
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