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3 years ago

1.

1 answer:

8 0

10.2, because it already gave you the r and d, so finding the t would mean dividing, so 402.9 / 39.5 = 10.2, hope that helps!

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please help asap!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Phantasy [73]

Answer:

Area = 7.853981 in^2 (2.5 Pi)

Perimeter = 11.42478 in (3.63Pi)

Step-by-step explanation:

Area

Lg semi circle area = Pi(2^2)(0.5) = 3.141593(4)0.5) = 6.283185 in^2

Sm semi circle area = Pi(1^2)(0.5) = 3.141593(2)(0.5) = 1.570796 in^2

added together = 7.853981 in^2

Perimeter

Lg semi circle perimeter = Pi(4)(0.5) + 2 = 8.283185 in

Sm semi circle perimeter = Pi(2)(0.5) = 3.141593 in

added together = 11.42478 in

5 0

3 years ago

Solve for m. 2 √5= 3 = 3 6+25 26-25 02.5-6

Sloan [31]

Answer:

Simplify the matrix.

2√5=3=3,31,1,−3.5

Step-by-step explanation:

5 0

3 years ago

If tan theta= -3/4 and θ is in quadrant IV, cos2 theta= and tan2 theta= .

Oksanka [162]

$\cos 2(\text { theta })=\frac{7}{25}$

$\tan 2(\text { theta })=-\frac{24}{7}$

Step-by-step explanation:

Given data:

$\tan \theta=-\frac{3}{4}$

To find:

cos 2 theta and tan 2 theta

Solution:

Hence, the trigonometric formula for those are below,

$\tan 2(\text { theta })=\frac{2 \tan (\text { theta })}{1-\tan ^{2}(\text { theta })}$

$\cos 2(\text { theta })=\frac{1-\tan ^{2}(\text { theta })}{1+\tan ^{2}(\text { thet } a)}$

Now, find the required data by substituting the given value. We get,

$\tan 2(\text { theta })=\frac{2 \times\left(-\frac{3}{4}\right)}{1-\frac{9}{16}}=-\frac{3}{2} \times \frac{16}{7}=-\frac{24}{7}$

Similarly for cos 2 theta,

$\cos 2(\text { theta })=\frac{1-\frac{9}{16}}{1+\frac{9}{16}}=\frac{7}{16} \times \frac{16}{25}=\frac{7}{25}$

3 0

3 years ago

Small earthworms travel at speeds of about 0.2 centimeters per second. What is this speed in meters per second?

Sonja [21]

The answer is b because is basically just gave you the answer in the question

4 0

3 years ago

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Li Na is going to plant 63 tomato plants and 81 rhubarb plants. Li Na would like to plant the plants in rows where each row has

avanturin [10]

Given:
63 tomato plants
81 rhubarb plants

63 / 9 = 7
81 / 9 = 9

The greatest number of rows Li Na can plant is 9 rows with 7 tomato plants and 9 rhubarb plants per row.

6 0

3 years ago

Read 2 more answers