


with that template in mind, let's see.
to the left by 3 units, C = +3
up by 1 unit, D = 1
![\bf g(x)=-x^2\\\\\\ g(x)=-1(1x+\stackrel{C}{0})^2+\stackrel{D}{0}\implies g(x)=-1(1x+3)^2+1 \\\\\\ g(x)=-(x+3)^2+1\impliedby f(x)\qquad \qquad f(-1.5)=-[(-1.5)+3]^2+1](https://tex.z-dn.net/?f=%5Cbf%20g%28x%29%3D-x%5E2%5C%5C%5C%5C%5C%5C%20g%28x%29%3D-1%281x%2B%5Cstackrel%7BC%7D%7B0%7D%29%5E2%2B%5Cstackrel%7BD%7D%7B0%7D%5Cimplies%20g%28x%29%3D-1%281x%2B3%29%5E2%2B1%0A%5C%5C%5C%5C%5C%5C%0Ag%28x%29%3D-%28x%2B3%29%5E2%2B1%5Cimpliedby%20f%28x%29%5Cqquad%20%5Cqquad%20f%28-1.5%29%3D-%5B%28-1.5%29%2B3%5D%5E2%2B1)
and surely you know how much that is.
Let x, y be numbers.
The addition identity property states that 0 + x = x.
The commutative property states that x + y = y + x
Answer:
Step-by-step explanation:
slope = 

Point-slope form:
y - y1 = m(x - x1)
y - 5 = -10(x - 8)
You would save $2447.40 for the emergency fund
Answer: For 95% Confidence Interval:
Upper Limit = 110.2
Lower Limit = 97.8
95% Confidence Interval = [97.8, 110.2]
Step-by-step explanation:
Given that,
Mean(M) = 104
Standard Deviation(SD) = 10
Sample Size(n) = 10
Formula for calculating 95% Confidence Interval are as follows:
Standard error(SE) =
= 
= 3.164
⇒ M ±
× SE
= 104 ± (1.96)(3.164)
= 104 ± 6.20
∴ Upper Limit = 104 + 6.20 = 110.2
Lower Limit = 104 - 6.20 = 97.8
So,
95% Confidence Interval = [97.8, 110.2]