The statement which does not adequately describe a developmental progression is Choice C- A developmental progression is a skill check- list that four-years- olds must master to be prepared for kindergarten.
<h3>What is developmental progression?</h3>
The Developmental Progression of Functional Skills is a concept which describes the child's growth in which case, the child's develops relationship with family members and a sense of self in the process and this concept in discuss is not limited to four-year olds.
Read more on developmental progression;
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Answer:
Independent variable: amount of water
Dependent variable: growth of the plant
Step-by-step explanation:
In the statement "Julie notices that her plant grows one inch for every liter of water that it receives" it is implied that the growth of the plant is related proportionally to the amount of water it receives.
We know the amount of growth in function of the amount of water
The dependant variable, the result, is the growth of the plant.
Then, the independent variable is the amount of water, as it is the input to calculate the amount of growth.
7m
1.75 divided by 2.25 = 0.77777777...
0.77777777.. times by 9 = 7
9514 1404 393
Answer:
- sin(Ф) = (4/41)√41; csc(Ф) = (√41)/4
- cos(Ф) = (5/41)√41; sec(Ф) = (√41)/5
- tan(Ф) = 4/5; cot(Ф) = 5/4
Step-by-step explanation:
The mnemonic SOH CAH TOA can help you with three of the functions. Then you need to remember the relations between those and the other three.
Tan = Opposite/Adjacent
tan(Ф) = 4/5
This suggests you can draw a triangle like the one attached that has adjacent side 5 and opposite side 4. Then hypotenuse can be found from the Pythagorean theorem:
AC² = AB² +BC² = 5² +4² = 41
AC = √41 . . . . . hypotenuse
Then the other trig functions are ...
Sin = Opposite/Hypotenuse
sin(Ф) = 4/√41 = (4/41)√41
Cos = Adjacent/Hypotenuse
cos(Ф) = 5/√41 = (5/41)√41
And the reciprocal functions are ...
csc(Ф) = 1/sin(Ф) = (√41)/4
sec(Ф) = 1/cos(Ф) = (√41)/5
cot(Ф) = 1/tan(Ф) = 5/4
<span>This would be a bell curve with a z-score of greater than +2.00, since 3 minutes is exactly two standard deviations greater than the mean of 2.00. Looking at a z-score table for the proportion of the curve that lies in the 1-tailed area greater than 2.00, we find that the value is .0228. This would be the probability that the conversation is over three minutes: 0.0228 or 2.28%.</span>
