All categories

2 years ago

Help meeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

Mathematics

2 answers:

amid [387]2 years ago

3 0

Anwser is B I got it right on the test

vfiekz [6]2 years ago

3 0

The answer is B because it’s right

You might be interested in

3 ÷ 1/2 what is it?

Alja [10]

$3\div\dfrac{1}{2}=3\cdot2=6$

8 0

3 years ago

Read 2 more answers

What is -4 (-6x + 3) = 12

IgorC [24]

Answer: x = 1

Step-by-step explanation:

Simplifying

-4(-6x + 3) = 12

Reorder the terms:

-4(3 + -6x) = 12

(3 * -4 + -6x * -4) = 12

(-12 + 24x) = 12

Solving

-12 + 24x = 12

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '12' to each side of the equation.

-12 + 12 + 24x = 12 + 12

Combine like terms: -12 + 12 = 0

0 + 24x = 12 + 12

24x = 12 + 12

Combine like terms: 12 + 12 = 24

24x = 24

Divide each side by '24'.

x = 1

Simplifying

x = 1

6 0

3 years ago

Read 2 more answers

Lauren took 12 hours to read a 360 page book. At this rate, how long will it take her to read a 1200 page book?

Sliva [168]

Answer:

About 48 hours or 2 days.

Step-by-step explanation:

360 + 360 = 720 + 360 = 1080 + 360 = 1440

12x4=48

4 0

3 years ago

Can someone help me asap !!?

denis23 [38]

C. 4
Because the rule of the graph is $1.50 per pound of apple, so you have to divide $6.00 by $1.50 and that gives you the answer.
I hope I helped
Please make me brainliest

5 0

3 years ago

If <img src="https://tex.z-dn.net/?f=%5Crm%20%5C%3A%20x%20%3D%20log_%7Ba%7D%28bc%29" id="TexFormula1" title="\rm \: x = log_{a}(

timama [110]

Use the change-of-basis identity,

$\log_x(y) = \dfrac{\ln(y)}{\ln(x)}$

to write

$xyz = \log_a(bc) \log_b(ac) \log_c(ab) = \dfrac{\ln(bc) \ln(ac) \ln(ab)}{\ln(a) \ln(b) \ln(c)}$

Use the product-to-sum identity,

$\log_x(yz) = \log_x(y) + \log_x(z)$

to write

$xyz = \dfrac{(\ln(b) + \ln(c)) (\ln(a) + \ln(c)) (\ln(a) + \ln(b))}{\ln(a) \ln(b) \ln(c)}$

Redistribute the factors on the left side as

$xyz = \dfrac{\ln(b) + \ln(c)}{\ln(b)} \times \dfrac{\ln(a) + \ln(c)}{\ln(c)} \times \dfrac{\ln(a) + \ln(b)}{\ln(a)}$

and simplify to

$xyz = \left(1 + \dfrac{\ln(c)}{\ln(b)}\right) \left(1 + \dfrac{\ln(a)}{\ln(c)}\right) \left(1 + \dfrac{\ln(b)}{\ln(a)}\right)$

Now expand the right side:

$xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} \\\\ ~~~~~~~~~~~~+ \dfrac{\ln(c)\ln(a)}{\ln(b)\ln(c)} + \dfrac{\ln(c)\ln(b)}{\ln(b)\ln(a)} + \dfrac{\ln(a)\ln(b)}{\ln(c)\ln(a)} \\\\ ~~~~~~~~~~~~ + \dfrac{\ln(c)\ln(a)\ln(b)}{\ln(b)\ln(c)\ln(a)}$

Simplify and rewrite using the logarithm properties mentioned earlier.

$xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} + \dfrac{\ln(a)}{\ln(b)} + \dfrac{\ln(c)}{\ln(a)} + \dfrac{\ln(b)}{\ln(c)} + 1$

$xyz = 2 + \dfrac{\ln(c)+\ln(a)}{\ln(b)} + \dfrac{\ln(a)+\ln(b)}{\ln(c)} + \dfrac{\ln(b)+\ln(c)}{\ln(a)}$

$xyz = 2 + \dfrac{\ln(ac)}{\ln(b)} + \dfrac{\ln(ab)}{\ln(c)} + \dfrac{\ln(bc)}{\ln(a)}$

$xyz = 2 + \log_b(ac) + \log_c(ab) + \log_a(bc)$

$\implies \boxed{xyz = x + y + z + 2}$

(C)

6 0

2 years ago